How to sort a Python dictionary by value?

Possible Duplicate:
In Python how do I sort a list of dictionaries by values of the dictionary?
Sorting Python dictionary based on nested dictionary values

I have dictionary of the form as mentioned below:

a_dict = { 'e': (1, 100), 'a': (2, 3) }

I am unable to sort it by the second element of the tuple. The resultant dictionary will appear as below:

a_dict = { 'a': (2, 3), 'e': (1, 100) }

---

Dictionaries can't be sorted as such, but you can sort their contents:

sorted(a_dict.items(), key=lambda (k, (v1, v2)): v2)
sorted(a_dict.items(), key=lambda item: item[1][1])    # Python 3

You can put the results into a collections.OrderedDict (since 2.7):

OrderedDict(sorted(a_dict.items(), key=lambda (k, (v1, v2)): v2))
OrderedDict(sorted(a_dict.items(), key=lambda item: item[1][1])    # Python 3

---

In your example you are using list of dictionaries . Sorting dict by key:

mydict = {'carl':40,
          'alan':2,
          'bob':1,
          'danny':3}

for key in sorted(mydict.iterkeys()):
    print "%s: %s" % (key, mydict[key])

alan: 2
bob: 1
carl: 40
danny: 3

If you want to sort dict by value, please see Sort a Python dictionary by value

链接地址: http://www.djcxy.com/p/70760.html

上一篇: 在Python中排序关联数组

下一篇: 如何按值排序Python字典？