Sort by list in list in python?

2018-06-25 06:42:53

This question already has an answer here:

How do I sort a list of dictionaries by values of the dictionary in Python? 17 answers

你可以使用带键参数的list.sort() ，将一个lambda表达式传递给key参数 -

In [45]: l = [{"id":"21", "region" :['2', '6', '4']}, {"id":"12", "region" :['1', '3', '8']}]

In [46]: l.sort(key=lambda x: x['region'][1])

In [47]: l
Out[47]:
[{'id': '12', 'region': ['1', '3', '8']},
 {'id': '21', 'region': ['2', '6', '4']}]

参考sorted(iterable, cmp=None, key=None, reverse=False)

>>> l = [{"id":"21", "region" :['2', '6', '4']}, {"id":"12", "region" :['1', '3', '8']}]

>>> print sorted(l, key=lambda x: x['region'][1], reverse=False)
[{'region': ['1', '3', '8'], 'id': '12'}, {'region': ['2', '6', '4'], 'id': '21'}]

>>> print l
[{'region': ['2', '6', '4'], 'id': '21'}, {'region': ['1', '3', '8'], 'id': '12'}]

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