用另一个NSMutableArray将自定义对象排序为NSMutableArray

这个问题在这里已经有了答案：

我如何排序一个NSMutableArray中的自定义对象？ 25个答案

并排排列两个NSArrays 4个答案

---

guideArray = < YOUR SECOND ARRAY WITH STRING OBJECT >;    
unsortedArray = < YOUR FIRST ARRAY WITH CUSTOM OBJECT >;

[unsortedArray sortUsingComparator:^(id o1, id o2) {
    Items *item1 = o1;
    Items *item2 = o2;
    NSInteger idx1 = [guideArray indexOfObject:item1.ItemID];
    NSInteger idx2 = [guideArray indexOfObject:item2.ItemID];
    return idx1 - idx2;
}];
NSLog(@"%@",unsortedArray);

---

将自定义对象存储在以itemID为关键字的字典中，使用此字典作为查找来对对象进行排序：

    NSArray *objects; // your objects
    NSMutableArray *hintArray; // your sorted IDs
    NSMutableDictionary *lookupDict = [[NSMutableDictionary alloc] initWithCapacity:[objects count]];
    NSMutableArray *sortedObjects = [[NSMutableArray alloc] initWithCapacity:[hintArray count]];

    for (id object in objects) {
        [lookupDict setValue:object forKey:[object itemID]];
    }

    for (id hint in hintArray) {
        [sortedObjects addObject:[lookupDict valueForKey:hint]];
    }

编辑：与就地排序objects解决方案：

    NSMutableArray *objects;
    NSMutableArray *hintArray;
    NSMutableDictionary *lookupDict = [[NSMutableDictionary alloc] initWithCapacity:[hintArray count]];

    int i = 0;
    for (NSString *itemID in hintArray) {
        [lookupDict setValue:[NSNumber numberWithInt:i] forKey:itemID];
        i++;
    }

    [objects sortUsingComparator:^NSComparisonResult(id obj1, id obj2) {
        return [[lookupDict valueForKey:[obj1 itemID]] compare:[lookupDict valueForKey:[obj2 itemID]]];
    }];

---

您可以使用以下语法比较两个对象： -

[items sortUsingComparator:^NSComparisonResult(Attribute *obj1, Attribute *obj2) 
{
    return [[NSNumber numberWithInt:[stringOrder indexOfObject:obj1.itemID]] compare:[NSNumber numberWithInt:[stringOrder indexOfObject:obj2.itemID]]]
}];

否则你可以使用下面的代码片段：

NSArray* sortedKeys = [dict keysSortedByValueUsingComparator:^(id obj1, id obj2)
 {
    return [obj1 compareTo:obj2];
 }

享受编程！

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