point of arguments in main function

 

This question already has an answer here:

  • What does int argc, char *argv[] mean? 8 answers

    • Depending on what type of application you are developing this may or may not be relevant to you. But arguments are intended for your command line arguments that are passed to the application at run time.

    The prototype is 

    int main (int argc, char ** argv);

    If you invoke your application from the command line 

    ./a.out foo bar

    Then main will get passed 

    argc = 2
argv = {"foo", "bar", NULL}

    The other valid prototype for main is 

    int main(void);

    If you don't want arguments. Any other prototype will be rejected by the compiler.

    它们通常用于提供命令行参数。

    链接地址: http://www.djcxy.com/p/72186.html

    上一篇: c无限循环错误

    下一篇: 主要功能中的论点点