How does Unary Operator '&' work
How does the unary operator '&' work ?
In a test project i ran this code:
int num = 50, num2 = 100;
int x = num & num2;
result: x = 32
int num = 100, num2 = 90;
int x = num & num2;
result :x = 64
How is this calculated ?
From MSDN:
Binary & operators are predefined for the integral types and bool. For integral types, & computes the logical bitwise AND of its operands. For bool operands, & computes the logical AND of its operands; that is, the result is true if and only if both its operands are true.
In your case it is integeral type version.
So:
50 in binary is 00110010
100 in binary is 01100100
AND result is 00100000 (32 dec)
Bitwise operator works on bits and perform bit-by-bit operation.
Binary AND Operator copies a bit to the result if it exists in both operands.
(A & B) = 12, i.e., 0000 1100
Binary values
50 (10 ) = 0110010 (2)
100 (10) = 1100100 (2)
And a logical AND is used so only the bits where both values are 1 are now one resulting in:
0100000 (2) = 32 (10)
and
100 (10) = 1100100 (2)
AND
90 (10) = 1011010 (2)
------------------------
64 (10) = 1000000(2)
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