Is there any danger in calling free() or delete instead of delete[]?
Possible Duplicate:
( POD )freeing memory : is delete[] equal to delete ?
Does delete deallocate the elements beyond the first in an array?
char *s = new char[n];
delete s;
Does it matter in the above case seeing as all the elements of s are allocated contiguously, and it shouldn't be possible to delete only a portion of the array?
For more complex types, would delete call the destructor of objects beyond the first one?
Object *p = new Object[n];
delete p;
How can delete[] deduce the number of Object s beyond the first, wouldn't this mean it must know the size of the allocated memory region? What if the memory region was allocated with some overhang for performance reasons? For example one could assume that not all allocators would provide a granularity of a single byte. Then any particular allocation could exceed the required size for each element by a whole element or more.
For primitive types, such as char , int , is there any difference between:
int *p = new int[n];
delete p;
delete[] p;
free p;
Except for the routes taken by the respective calls through the delete -> free deallocation machinery?
It's undefined behaviour (most likely will corrupt heap or crash the program immediately) and you should never do it. Only free memory with a primitive corresponding to the one used to allocate that memory.
Violating this rule may lead to proper functioning by coincidence, but the program can break once anything is changed - the compiler, the runtime, the compiler settings. You should never rely on such proper functioning and expect it.
delete[] uses compiler-specific service data for determining the number of elements. Usually a bigger block is allocated when new[] is called, the number is stored at the beginning and the caller is given the address behind the stored number. Anyway delete[] relies on the block being allocated by new[] , not anything else. If you pair anything except new[] with delete[] or vice versa you run into undefined behaviour.
Read the FAQ: 16.3 Can I free() pointers allocated with new? Can I delete pointers allocated with malloc()?
Does it matter in the above case seeing as all the elements of s are allocated contiguously, and it shouldn't be possible to delete only a portion of the array?
Yes it does.
How can delete[] deduce the number of Objects beyond the first, wouldn't this mean it must know the size of the allocated memory region?
The compiler needs to know. See FAQ 16.11
Because the compiler stores that information.
What I mean is the compiler needs different delete s to generate appropriate book-keeping code. I hope this is clear now.
Yes, this is dangerous!
Dont do it!
It will lead to programm crashes or even worse behavior!
For objects allocated with new you MUST use delete ;
For objects allocated with new [] you MUST use delete [] ;
For objects allocated with malloc() or calloc() you MUST use free() ;
Be aware also that for all these cases its illegal to delete/free a already deleted/freed pointer a second time. free may also NOT be called with null. calling delete/delete[] with NULL is legal.
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