在c ++中重载<<运算符?
我试图重载<<运算符,但我收到了这样的错误:
传递const std::ostream' as
此参数的std :: basic_ostream <_CharT,_Traits>&std :: basic_ostream <_CharT,_Traits> ::运算符<<(const void *)[with _CharT = char,_Traits = std :: char_traits]'丢弃限定符
这是我的代码:
#include<iostream>
using namespace std;
class nod{
protected:
int info;
nod *next;
friend class lista;
friend const ostream &operator<<(const ostream &,lista&);
};
class lista
{nod *first, *last;
public:
lista()
{first=new nod;
last=new nod;
first=last=NULL;}
void insert(int);
// void remove();
void afisare();
nod *get_first(){ return first;};
};
void lista::insert(int x)
{ nod *nou=new nod;
nou->info=x;
if(!first)
first=last=nou;
else
nou->next=first;
first=nou;
last->next=first;}
const ostream &operator<<(const ostream &o,lista &A)
{nod *curent=new nod;
o<<"Afisare: ";
curent=A.get_first();
if(curent)
o<<curent->info<<" ";
curent=curent->next;
while(curent!=A.get_first())
{o<<curent->info<<" ";
curent=curent->next;}
return o;
}
int main()
{lista A;
A.insert(2);
A.insert(6);
A.insert(8);
A.insert(3);
A.insert(5);
cout<<A;
system("pause");
return 0;}
这个const ostream&operator <<(const ostream&o,lista&A)
应该:
ostream &operator<<(ostream &o,lista &A)
因为实际的流在您写入时会被修改。
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