What is the order of execution in try,catch and finally
This question already has an answer here:
http://docs.oracle.com/javase/tutorial/essential/exceptions/finally.html
http://docs.oracle.com/javase/specs/jls/se7/html/jls-14.html#jls-14.20.2
finally always executes. If there is a return in try , the rest of try and catch don't execute, then finally executes (from innermost to outermost), then the function exits.
first of all you need to go for documentation and understand the concept correctly you can refer these documentation
http://docs.oracle.com/javase/tutorial/essential/exceptions/finally.html
http://docs.oracle.com/javase/specs/jls/se7/html/jls-14.html#jls-14.20.2
here on stackoverflow no one should explain because this site not a toturial purpose basically.
Normally order execution order of try-catch-finally is first try , then if exception trows and caught will execute the catch . If exception caught or not finally will always execute.
If return in your try , execution in try will stop there and will execute finally . if exception throws and caught before that return normal execution order will follows.
Let's run following code
public static void main(String[] args) {
String[] arr=getInfo();
for(String i:arr){
System.out.println(i);
}
}
public static String[] getInfo(){
String[] arr=new String[3];
try {
arr[0]="try";
return arr;
}catch (Exception e){
arr[1]="catch";
return arr;
}finally {
arr[2]="finally";
return arr;
}
}
Out put
try // return in try
null
finally // returning value in finally.
Now this out put explain the every thing you want. finally runs while there is a return in try .
If there a System.exit(0) in your try , finally is not going to execute.
上一篇: 终于总是被叫？