form "if" in C++
Possible Duplicate:
Python Ternary Operator
Is there a way to write this C/C++ code in Python? a = (b == true ? "123" : "456" )
a = '123' if b else '456'
While a = 'foo' if True else 'bar' is the more modern way of doing the ternary if statement (python 2.5+), a 1-to-1 equivalent of your version might be:
a = (b == True and "123" or "456" )
... which in python should be shortened to:
a = b is True and "123" or "456"
... or if you simply want to test the truthfulness of b's value in general...
a = b and "123" or "456"
? : ? : can literally be swapped out for and or
我的神秘版本...
a = ['123', '456'][b == True]
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