Is it more efficient to use a flag or an if clause?
In a Java loop, is it more efficient to use a boolean
flag instead of an if
statement?
Take a look at these two bits of code.
Using a flag:
public boolean isSomethingForAnyone() {
boolean flag = false;
for (Item item : listOfItems) {
flag = flag || item.isSomething();
}
return flag;
}
Using an if
statement:
public boolean isSomethingForAnyone() {
for (Item item : listOfItems) {
if (item.isSomething())
return true;
}
return false;
}
The method with the if
statement is of course faster if isSomething()
return true
on the first iteration. But, is it faster on average or does the branching slow it down enough that it is slower? Also, is the situation different if the loop is faster? Here I used a for-each loop for simplicity, which I believe is slower than iterating over an array with a counter.
The two pieces of code aren't quite equivalent.
Even though you only call item.isSomething()
as many times as you need to (contrary to my original answer), the first version still keeps trying to iterate over the rest of the collection.
Imagine an implementation of Item.isSomething()
which modified the collection in which the item is found (if it returns true
). At that point, the first piece of code would throw a ConcurrentModificationException
assuming it's a "regular" collection - whereas the second piece of code would just return true
.
Fundamentally, the second piece of code is more efficient: it only iterates through as much of the list as is required to determine the answer, instead of through everything. It may well be that the performance different is irrelevant - particularly if the collection is small - but that depends on the context.
Which you find more readable is a different matter - it's likely that the efficiency won't be significant, although that depends on the context. Personally I find the second version more readable as well as more efficient, so I'd always use it. (Well, I'd add braces around the body of the if
statement, but that's all.)
are you doing this loop literally a billion times? if not, the difference is probably impossible to measure.
you could look at the generated bytecode and see exactly what is going on, but the compiler and jit and the vm itself would probably optimize away any differences anyway.
If you want to know which is 'faster' on your machine then run it.
If we want to know which takes more instructions to perform then we can look at the bytecode.
For the first method we get this (call javap -c
)
Code:
0: iconst_0
1: istore_1
2: getstatic #2 // Field listOfItems:Ljava/util/List;
5: invokeinterface #3, 1 // InterfaceMethod java/util/List.iterator:()Ljava/util/Iterator;
10: astore_2
11: aload_2
12: invokeinterface #4, 1 // InterfaceMethod java/util/Iterator.hasNext:()Z
17: ifeq 50
20: aload_2
21: invokeinterface #5, 1 // InterfaceMethod java/util/Iterator.next:()Ljava/lang/Object;
26: checkcast #6 // class Item
29: astore_3
30: iload_1
31: ifne 41
34: aload_3
35: invokevirtual #7 // Method Item.isSomething:()Z
38: ifeq 45
41: iconst_1
42: goto 46
45: iconst_0
46: istore_1
47: goto 11
50: iload_1
51: ireturn
We're interested in the interior of the loop ie lines 29-46 (lines 11-26 are Iterator stuff). So about 10 instructions.
For the second method we get this:
Code:
0: getstatic #2 // Field listOfItems:Ljava/util/List;
3: invokeinterface #3, 1 // InterfaceMethod java/util/List.iterator:()Ljava/util/Iterator;
8: astore_1
9: aload_1
10: invokeinterface #4, 1 // InterfaceMethod java/util/Iterator.hasNext:()Z
15: ifeq 40
18: aload_1
19: invokeinterface #5, 1 // InterfaceMethod java/util/Iterator.next:()Ljava/lang/Object;
24: checkcast #6 // class Item
27: astore_2
28: aload_2
29: invokevirtual #7 // Method Item.isSomething:()Z
32: ifeq 37
35: iconst_1
36: ireturn
37: goto 9
40: iconst_0
41: ireturn
The lines of interest are 27-37. So 7 instructions.
From a numbers point of view the second method comes out on top (note that we assume that all stack operations take the same time to perform).
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