Making letters uppercase using re.sub in python?
In many programming languages, the following
find foo([az]+)bar and replace with GOOU1GAR
will result in the entire match being made uppercase. I can't seem to find the equivalent in python; does it exist?
You can pass a function to re.sub() that will allow you to do this, here is an example:
def upper_repl(match):
return 'GOO' + match.group(1).upper() + 'GAR'
And an example of using it:
>>> re.sub(r'foo([a-z]+)bar', upper_repl, 'foobazbar')
'GOOBAZGAR'
Do you mean something like this?
>>>x = "foo spam bar"
>>>re.sub(r'foo ([a-z]+) bar', lambda match: r'foo {} bar'.format(match.group(1).upper()), x)
'foo SPAM bar'
For reference, here's the docstring of re.sub (emphasis mine).
Return the string obtained by replacing the leftmost non-overlapping occurrences of the pattern in string by the replacement repl. repl can be either a string or a callable ; if a string, backslash escapes in it are processed. If it is a callable, it's passed the match object and must return a replacement string to be used.
You could use some variation of this:
s = 'foohellobar'
def replfunc(m):
return m.groups()[0]+m.groups()[1].upper()+m.groups()[2]
re.sub('(foo)([a-z]+)(bar)',replfunc,s)
gives the output:
'fooHELLObar'