RegEx多个捕获组替换为一个字符串

我有一串数据...

"123456712J456","D","TEST1~TEST2~TEST3~TEST4~TEST5"

我想采取以下字符串，并使5个字符串。

"123456712J456","D","TEST1"
"123456712J456","D","TEST2"
"123456712J456","D","TEST3"
"123456712J456","D","TEST4"
"123456712J456","D","TEST5"

我目前有以下正则表达式...

//In a program like Textpad
<FIND> "(.{13})","D","([^~]*)~(.*)
<REPLACE> "1","D","2"n"1","D","3

//On the regex101 site
"(.{13})","D","([^~]*)~(.*)

现在，如果我运行这5次，它会正常工作。 问题是有未知的行数。 例如...

"123456712J456","D","TEST1~TEST2~TEST3~TEST4~TEST5"
"123456712J457","D","TEST1~TEST2~TEST3"
"123456712J458","D","TEST1~TEST2"
"123456712J459","D","TEST1~TEST2~TEST3~TEST4"

我希望能够使用MULTI捕获组来完成这项工作。 我发现这个页面谈论重复捕捉组和捕捉重复组之间的常见错误。 我需要捕捉一个重复的组。 出于某种原因，我只是无法让我的工作正确。 其他人有想法？

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资源：

http://www.regular-expressions.info/captureall.html

http://regex101.com/

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试试这个，看demo.Just俱乐部match1和rest of the matches 。

http://regex101.com/r/yR3mM3/17

正则表达式：

(.*,)|([^"~]+)

例：

"1234567123456","T","TEST1~TEST2~TEST3~TEST4~TEST5"

结果：

MATCH 1
  1.    [0-20]  `"1234567123456","T",`

MATCH 2
  2.    [21-26] `TEST1`

MATCH 3
  2.    [27-32] `TEST2`

MATCH 4
  2.    [33-38] `TEST3`

MATCH 5
  2.    [39-44] `TEST4`

MATCH 6
  2.    [45-50] `TEST5`

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