Match the first word then second letter of a string
How would you write a MySQL regex pattern that matches the full first word and the first character of the second word in a string. The string does not actually have to begin with a word. Case does not matter.
When searching for a string in which the first word occurrence is "Stack" and the next word begins with "O", the regex pattern should return true for all of the following:
and will fail if "Stack" is not the first word occurrence or the second word does not begin with an "O", like for the following:
I have tried some patterns but only came up with the following:
SELECT * FROM members WHERE description REGEX '^[[:<:]]Stack[[:>:]].+[[:<:]]O'
The problem here is:
+=,Stack
It will work if I can find the first and second word boundary.
我认为这个表达可以做你想做的事情:
where description rlike '^[^a-zA-Z]*Stack [^a-zA-Z]*O'
链接地址: http://www.djcxy.com/p/75348.html
上一篇: 找到匹配的词
下一篇: 匹配字符串的第一个字,然后匹配第二个字母