使用正则表达式在NSString中查找/替换子字符串
我想使用正则表达式来查找正则表达式模式的每个实例Ie &*; 在我的字符串中，并从中删除，返回值是没有任何匹配的原始字符串。 也希望使用相同的功能来匹配单词之间的多个空格，并改为使用单个空格。 找不到这样的功能。
示例输入字符串
NSString *str = @"123 &1245; Ross Test 12";
返回值应该是
123 Ross Test 12
如果任何匹配这个模式的东西"&*或者多个空格并且用@"";替换它@"";
NSString *string = @"123 &1245; Ross Test 12";
NSError *error = nil;
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:@"&[^;]*;" options:NSRegularExpressionCaseInsensitive error:&error];
NSString *modifiedString = [regex stringByReplacingMatchesInString:string options:0 range:NSMakeRange(0, [string length]) withTemplate:@""];
NSLog(@"%@", modifiedString);
在String扩展中使用正则表达式替换代码的字符串
Objective-C的
@implementation NSString(RegularExpression)
- (NSString *)replacingWithPattern:(NSString *)pattern withTemplate:(NSString *)withTemplate error:(NSError **)error {
NSRegularExpression *regex = [NSRegularExpression regularExpressionWithPattern:pattern
options:NSRegularExpressionCaseInsensitive
error:error];
return [regex stringByReplacingMatchesInString:self
options:0
range:NSMakeRange(0, self.length)
withTemplate:withTemplate];
}
@end
解决
NSString *string = @"123 &1245; Ross Test 12";
// remove all matches string
NSString *result = [string replacingWithPattern:@"&[d]+?;" withTemplate:@"" error:nil];
// result = "123 Ross Test 12"
或者更多
NSString *string = @"123 + 456";
// swap number
NSString *result = [string replacingWithPattern:@"([d]+)[ +]+([d]+)" withTemplate:@"$2 + $1" error:nil];
// result = 456 + 123
Swift2
extension String {
func replacing(pattern: String, withTemplate: String) throws -> String {
let regex = try NSRegularExpression(pattern: pattern, options: .CaseInsensitive)
return regex.stringByReplacingMatchesInString(self, options: [], range: NSRange(0..<self.utf16.count), withTemplate: withTemplate)
}
}
Swift3
extension String {
func replacing(pattern: String, withTemplate: String) throws -> String {
let regex = try RegularExpression(pattern: pattern, options: .caseInsensitive)
return regex.stringByReplacingMatches(in: self, options: [], range: NSRange(0..<self.utf16.count), withTemplate: withTemplate)
}
}
使用
var string = "1!I 2"want 3#to 4$remove 5%all 6&digit and a char right after 7'from 8(string"
do {
let result = try string.replacing("[d]+.", withTemplate: "")
} catch {
// error
}
// result = "I want to remove all digit and a char right after from string"
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