modify a regex so that only [a

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How do you access the matched groups in a JavaScript regular expression? 14 answers

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截至2018年，Javascript最终支持lookbehind断言，所以一旦它实现，以下应该在最新的浏览器中工作：

test = "i am sam";

console.log(test.match(/(?<=i'm |i am )[a-zA-Z]+/))

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You could capture your words using a capturing group ([a-zA-Z]+) :

I ?['a]m ([a-zA-Z]+)

This would match

I          # Match I
 ?         # Match an optional white space
['a]m      # Match ' or a followed by an m and a whitespace
(          # Capture in a group
 [a-zA-Z]+ # Match lower or uppercase character one or more times
)          # Close capturing group

Your words are in group 1.

var pattern = /I ?['a]m ([a-zA-Z]+)/;
var strings = [
  "I am good at this",
  "I'm sam"
];

for (var i = 0; i < strings.length; i++) {
  console.log(strings[i].match(pattern)[1]);
}

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