Javascript Regexp dynamic generation from variables?

This question already has an answer here:

How do you use a variable in a regular expression? 16 answers

---

You have to use RegExp :

str.match(new RegExp(pattern1+'|'+pattern2, 'gi'));

---

When I'm concatenating strings, all slashes are gone.

If you have a backslash in your pattern to escape a special regex character, (like ( ), you have to use two backslashes in the string (because is the escape character in a string): new RegExp('(') would be the same as /(/ .

So your patterns have to become:

var pattern1 = ':(|:=(|:-(';
var pattern2 = ':(|:=(|:-(|:(|:=(|:-(';

---

使用以下内容：

var regEx = new RegExp(pattern1+'|'+pattern2, 'gi');

str.match(regEx);

---

您必须放弃正则表达式并使用对象构造函数，您可以将正则表达式作为字符串传递。

var regex = new RegExp(pattern1+'|'+pattern2, 'gi');
str.match(regex);

链接地址: http://www.djcxy.com/p/76820.html

上一篇: JS使用变量替换所有出现的字符串

下一篇: Javascript Regexp从变量动态生成？