Parsing XML in Python with regex
This question already has an answer here:
You normally don't want to use re.match
. Quoting from the docs:
If you want to locate a match anywhere in string, use search() instead (see also search() vs. match()).
Note:
>>> print re.match('>.*<', line)
None
>>> print re.search('>.*<', line)
<_sre.SRE_Match object at 0x10f666238>
>>> print re.search('>.*<', line).group(0)
>PLAINSBORO, NJ 08536-1906<
Also, why parse XML with regex when you can use something like BeautifulSoup
:).
>>> from bs4 import BeautifulSoup as BS
>>> line='<City_State>PLAINSBORO, NJ 08536-1906</City_State>'
>>> soup = BS(line)
>>> print soup.find('city_state').text
PLAINSBORO, NJ 08536-1906
请使用像ElementTree这样的XML解析器
>>> from xml.etree import ElementTree as ET
>>> line='<City_State>PLAINSBORO, NJ 08536-1906</City_State>'
>>> ET.fromstring(line).text
'PLAINSBORO, NJ 08536-1906'
re.match returns a match only if the pattern matches the entire string. To find substrings matching the pattern, use re.search.
And yes, this is a simple way to parse XML, but I would highly encourage you to use a library specifically designed for the task.
链接地址: http://www.djcxy.com/p/76846.html上一篇: 删除html链接的正则表达式
下一篇: 用正则表达式在Python中解析XML