regex to match EOF

I have some data that look like this

john, dave, chris
rick, sam, bob
joe, milt, paul

I'm using this regex to match the names

/(w.+?)(rn|n|,)/

which works for the most part but the file ends abruptly after the last word meaning the last value doesn't end in rn , n or , it ends with EOF. Is there a way to match EOF in regex so I can put it right in that second grouping?

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The answer to this question is Z took me awhile to figure it out, but it works now. Note that conversely, A matches beginning of the whole string (as opposed to ^ and $ matching the beginning of one line).

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EOF is not actually a character. If you have a multi-line string, then '$' will match the end of the string as well as the end of a line.

In Perl and its brethren, A and Z match the beginning and end of the string, totally ignoring line-breaks.

GNU extensions to POSIX regexes use ` and ' for the same things.

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Contrast the behavior of Ryan's suggested Z with z:

$ perl -we 'my $corpus = "hellon"; $corpus =~ s/Z/world/g; print(":$corpus:n")'
:helloworld
world:
$ perl -we 'my $corpus = "hellon"; $corpus =~ s/z/world/g; print(":$corpus:n")'
:hello
world:
$ 

perlre sez:

Z  Match only at end of string, or before newline at the end
z  Match only at end of string

A translation of the test case into Ruby (1.8.7, 1.9.2) behaves the same.

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