Global memory management in C++ in stack or heap?

If I declare a data structure globally in a C++ application , does it consume stack memory or heap memory ?

For eg

struct AAA
{

.../.../.
../../..
}arr[59652323];

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Since I wasn't satisfied with the answers, and hope that the sameer karjatkar wants to learn more than just a simple yes/no answer, here you go.

Typically a process has 5 different areas of memory allocated

Code - text segment

Initialized data – data segment

Uninitialized data – bss segment

Heap

Stack

If you really want to learn what is saved where then read and bookmark these:

COMPILER, ASSEMBLER, LINKER AND LOADER: A BRIEF STORY (look at Table w.5)

Anatomy of a Program in Memory

alt text http://www.tenouk.com/ModuleW_files/ccompilerlinker006.png

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The problem here is the question. Let's assume you've got a tiny C(++ as well, they handle this the same way) program like this:

/* my.c */

char * str = "Your dog has fleas.";  /* 1 */
char * buf0 ;                         /* 2 */

int main(){
    char * str2 = "Don't make fun of my dog." ;  /* 3 */
    static char * str3 = str;         /* 4 */
    char * buf1 ;                     /* 5 */
    buf0 = malloc(BUFSIZ);            /* 6 */
    buf1 = malloc(BUFSIZ);            /* 7 */

    return 0;
}

This is neither allocated on the stack NOR on the heap. Instead, it's allocated as static data, and put into its own memory segment on most modern machines. The actual string is also being allocated as static data and put into a read-only segment in right-thinking machines.

is simply a static allocated pointer; room for one address, in static data.

has the pointer allocated on the stack and will be effectively deallocated when main returns. The string, since it's a constant, is allocated in static data space along with the other strings.

is actually allocated exactly like at 2. The static keyword tells you that it's not to be allocated on the stack.

...but buf1 is on the stack, and

... the malloc'ed buffer space is on the heap.

And by the way., kids don't try this at home. malloc has a return value of interest; you should always check the return value.

For example:

char * bfr;
if((bfr = malloc(SIZE)) == NULL){
   /* malloc failed OMG */
   exit(-1);
}

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Usually it consumes neither. It tries to allocate them in a memory segment which is likely to remain constant-size for the program execution. It might be bss, stack, heap or data.

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