Toast消息不会在x秒内显示在碎片中？

我想在我的应用程序中每隔2秒显示一次敬酒信息，该信息处于碎片不活动状态，但在我的代码中，只显示一次我在下面分享我的代码，请帮忙。

public View onCreateView（LayoutInflater inflater，ViewGroup container，Bundle savedInstanceState）{rootView = inflater.inflate（R.layout.fragment_layout_one，container，false）;

    MapsInitializer.initialize(getActivity()); 

    mMapView = (MapView)rootView.findViewById(R.id.mapView); 
    mMapView.onCreate(mBundle); 


    MapsInitializer.initialize(getActivity()); 

    if (android.os.Build.VERSION.SDK_INT > 9) { 
        StrictMode.ThreadPolicy policy = new StrictMode.ThreadPolicy.Builder() 
        .permitAll().build(); 
        StrictMode.setThreadPolicy(policy); 
    } 

    /* new DownloadJSON().execute(); 
    setUpMapIfNeeded(rootView); */

     handler = new Handler();
    handler.postDelayed(new Runnable() {

        @Override
        public void run() {
            // TODO Auto-generated method stub
             new DownloadJSON().execute(); 
                setUpMapIfNeeded(rootView); 

             Toast.makeText(getActivity(), "Data Updated!!!! ", Toast.LENGTH_SHORT).show();
             Log.e("Data in Log", "");
        }
    }, 1000);

    new DownloadJSON().execute(); 
    setUpMapIfNeeded(rootView);

    /*LocationManager locman = (LocationManager)getActivity().getSystemService(Context.LOCATION_SERVICE);
    //locman.requestLocationUpdates(minTime, minDistance, criteria, intent);
    locman.requestLocationUpdates(LocationManager.GPS_PROVIDER, 1000, 10, this);*/




    return rootView; 
} 

---

它为我工作，你可以这些代码...

    final Handler handler = new Handler();
    timer = new Timer();
    TimerTask doAsynchronousTask = new TimerTask() {
        @Override
        public void run() {
            handler.post(new Runnable() {
                public void run() {
                    Log.e("run", "run");

                }
            });
        }
    };
    timer.schedule(doAsynchronousTask, 60000, 60000);

这些代码在每1Min后运行..

---

postDelayed只做一次事情，最简单的解决方案就是像这样重新发布任务：

final Handler handler = new Handler();
final Runnable repeatingToast = new Runnable() {

    @Override
    public void run() {
         Toast.makeText(getActivity(), "My text!!!",Toast.LENGTH_SHORT).show();
         if(your_condition) {
             handler.postDelayed(repeatingToast, 1000);
         }
    }
};
handler.postDelayed(repeatingToast, 1000);

---

Toast.LENGTH_LONG = 3500; // 3.5 seconds
Toast.LENGTH_SHORT  = 2000; // 2 seconds

所以你在第一个被解雇之前打电话给下一个Toast。在线程中尝试更长的时间。

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