Print current call stack from a method in Python code
在Python中，如何从方法内打印当前调用堆栈（用于调试目的）。
Here's an example of getting the stack via the traceback module, and printing it:
import traceback
def f():
g()
def g():
for line in traceback.format_stack():
print(line.strip())
f()
# Prints:
# File "so-stack.py", line 10, in <module>
# f()
# File "so-stack.py", line 4, in f
# g()
# File "so-stack.py", line 7, in g
# for line in traceback.format_stack():
If you really only want to print the stack to stderr, you can use:
traceback.print_stack()
Or to print to stdout (useful if want to keep redirected output together), use:
traceback.print_stack(file=sys.stdout)
But getting it via traceback.format_stack() lets you do whatever you like with it.
import traceback
traceback.print_stack()
inspect.stack() returns the current stack rather than the exception traceback:
import inspect
print inspect.stack()
See https://gist.github.com/FredLoney/5454553 for a log_stack utility function.
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