grep without showing path/file:line
How do you grep and only return the matching line? ie The path/filename is omitted from the results.
In this case I want to look in all .bar files in the current directory, searching for the term FOO
find . -name '*.bar' -exec grep -Hn FOO {} ;
No need to find . If you are just looking for a pattern within a specific directory, this should suffice:
grep -hn FOO /your/path/*.bar
Where -h is the parameter to hide the filename, as from man grep :
-h, --no-filename
Suppress the prefixing of file names on output. This is the default when there is only one file (or only standard input) to search.
Note that you were using
-H, --with-filename
Print the file name for each match. This is the default when there is more than one file to search.
Just replace -H with -h . Check man grep for more details on options
find . -name '*.bar' -exec grep -hn FOO {} ;
如果你运行man grep你会看到这个：
-h, --no-filename
Suppress the prefixing of file names on output. This is the default when there
is only one file (or only standard input) to search.
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