python search with image google images

i'm having a very tough time searching google image search with python. I need to do it using only standard python libraries (so urllib, urllib2, json, ..)

Can somebody please help? Assume the image is jpeg.jpg and is in same folder I'm running python from.

I've tried a hundred different code versions, using headers, user-agent, base64 encoding, different urls (images.google.com, http://images.google.com/searchbyimage?hl=en&biw=1060&bih=766&gbv=2&site=search&image_url={{URL To your image}}&sa=X&ei=H6RaTtb5JcTeiALlmPi2CQ&ved=0CDsQ9Q8, etc....)

Nothing works, it's always an error, 404, 401 or broken pipe :(

Please show me some python script that will actually seach google images with my own image as the search data ('jpeg.jpg' stored on my computer/device)

Thank you for whomever can solve this,

Dave:)

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I use the following code in Python to search for Google images and download the images to my computer:

import os
import sys
import time
from urllib import FancyURLopener
import urllib2
import simplejson

# Define search term
searchTerm = "hello world"

# Replace spaces ' ' in search term for '%20' in order to comply with request
searchTerm = searchTerm.replace(' ','%20')


# Start FancyURLopener with defined version 
class MyOpener(FancyURLopener): 
    version = 'Mozilla/5.0 (Windows; U; Windows NT 5.1; it; rv:1.8.1.11) Gecko/20071127 Firefox/2.0.0.11'
myopener = MyOpener()

# Set count to 0
count= 0

for i in range(0,10):
    # Notice that the start changes for each iteration in order to request a new set of images for each loop
    url = ('https://ajax.googleapis.com/ajax/services/search/images?' + 'v=1.0&q='+searchTerm+'&start='+str(i*4)+'&userip=MyIP')
    print url
    request = urllib2.Request(url, None, {'Referer': 'testing'})
    response = urllib2.urlopen(request)

    # Get results using JSON
    results = simplejson.load(response)
    data = results['responseData']
    dataInfo = data['results']

    # Iterate for each result and get unescaped url
    for myUrl in dataInfo:
        count = count + 1
        print myUrl['unescapedUrl']

        myopener.retrieve(myUrl['unescapedUrl'],str(count)+'.jpg')

    # Sleep for one second to prevent IP blocking from Google
    time.sleep(1)

You can also find very useful information here.

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Google图片搜索API已弃用，我们使用Google搜索使用REgex和美丽的汤下载图像

from bs4 import BeautifulSoup
import requests
import re
import urllib2
import os


def get_soup(url,header):
  return BeautifulSoup(urllib2.urlopen(urllib2.Request(url,headers=header)))

image_type = "Action"
# you can change the query for the image  here  
query = "Terminator 3 Movie"
query= query.split()
query='+'.join(query)
url="https://www.google.co.in/searches_sm=122&source=lnms&tbm=isch&sa=X&ei=4r_cVID3NYayoQTb4ICQBA&ved=0CAgQ_AUoAQ&biw=1242&bih=619&q="+query

print url
header = {'User-Agent': 'Mozilla/5.0'} 
soup = get_soup(url,header)

images = [a['src'] for a in soup.find_all("img", {"src": re.compile("gstatic.com")})]
#print images
for img in images:
  raw_img = urllib2.urlopen(img).read()
  #add the directory for your image here 
  DIR="C:UsershpPicturesvalentines"
  cntr = len([i for i in os.listdir(DIR) if image_type in i]) + 1
  print cntr
  f = open(DIR + image_type + "_"+ str(cntr)+".jpg", 'wb')
  f.write(raw_img)
  f.close()

链接地址: http://www.djcxy.com/p/83794.html

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