如何使用模式匹配找到重复的字符串？
我有一个类似这样的字符串：
[13:41:25] [100:Devnull]: 01:41:20, 13:41:21> |Hunit:Player-3693-07420299:DevnullYour [Chimaera Shot] hit |Hunit:Creature-0-3693-1116-3-87318-0000881AC4:Dungeoneer's Training DummyDungeoneer's Training Dummy 33265 Nature.
如果你想知道，它来自魔兽世界。
我想结束这样的事情：
[13:41:25] [100:Devnull]: 01:41:20, 13:41:21> Your [Chimaera Shot] hit Dungeoneer's Training Dummy 33265 Nature.
如果您注意到，“Dungeoneer's Training Dummy”会打印两次。 我设法摆脱了这样的第一个“| Hunit”部分：
str = "[13:41:25] [100:Devnull]: 01:41:20, 13:41:21> |Hunit:Player-3693-07420299:DevnullYour [Chimaera Shot] hit |Hunit:Creature-0-3693-1116-3-87318-0000881AC4:Dungeoneer's Training DummyDungeoneer's Training Dummy 33265 Nature."
str = string.gsub(str, "|Hunit:.*:.*Your", "Your")
其中返回这个：
print(str) # => [13:41:25] [100:Devnull]: 01:41:20, 13:41:21> Your [Chimaera Shot] hit |Hunit:Creature-0-3693-1116-3-87318-0000881AC4:Dungeoneer's Training DummyDungeoneer's Training Dummy 33265 Nature.
然后我添加第二个gsub：
str = string.gsub(str, "|Hunit:.*:", "")
print(str) # => [13:41:25] [100:Devnull]: 01:41:20, 13:41:21> Your [Chimaera Shot] hit Dungeoneer's Training DummyDungeoneer's Training Dummy 33265 Nature.
但显然，双重的“Dungeoneer's Training Dummy”字符串会重复出现。
我怎么能摆脱重复的字符串？ 这个字符串可以是其他任何东西，在这种情况下是“Dungeoneer's Training Dummy”，但它可以是任何其他目标的名称。
你可以尝试这样的事情：
str = "[13:41:25] [100:Devnull]: 01:41:20, 13:41:21> Your [Chimaera Shot] hit Dungeoneer's Training DummyDungeoneer's Training Dummy 33265 Nature."
-- find a string that starts with 'hit', has some number of non-digits
-- and ends with one or more digit and one or more characters.
-- these characters will be "captured" into three strings,
-- which are then passed to the "replacement" function.
-- the returned result of the function replaces the value in the string.
str = str:gsub("(hit%s+)([^%d]+)(%d+.+)", function(s1, s2, s3)
local s = s2:gsub("%s+$","") -- drop trailing spaces
if #s % 2 == 0 -- has an even number of characters
and s:sub(0, #s / 2) -- first half
== -- is the same
s:sub(#s / 2 + 1) -- as the second half
then -- return the second half
return s1..s:sub(#s / 2 + 1)..' '..s3
else
return s1..s2..s3
end
end)
print(str)
这将打印： [13:41:25] [100:Devnull]: 01:41:20, 13:41:21> Your [Chimaera Shot] hit Dungeoneer's Training Dummy
此代码将尝试提取目标的名称，并检查名称是否完全重复。 如果匹配失败，则返回原始字符串。
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