有没有办法计算NSString的行数？
可能重复：
如何计算Objective-C字符串（NSString）中的行数？
有没有办法计算NSString的行数？
NSString * myString = @"line 1 n line 2 n";
线= 3;
谢谢
尝试下面的代码。
NSString * myString = @"line 1 n line 2 n";
NSArray *list = [myString componentsSeparatedByString:@"n"];
NSLog(@"No of lines : %d",[list count]);
当心componentsSeparatedByString不够智能检测mac / windows / unix行结束。 在n上分离将适用于windows / unix行结尾，但不适用于传统的mac文件（并且有一些流行的mac编辑器仍然默认使用这些文件）。 你应该真的在检查rn和r 。
另外， componentsSeparatedByString:速度慢，内存不足。 如果你关心性能，你应该重复搜索换行符并计算结果数量：
NSString * myString = @"line 1 n line 2 n";
int lineCount = 1;
NSUInteger characterLocation = 0;
NSCharacterSet *newlineCharacterSet = [NSCharacterSet newlineCharacterSet];
while (characterLocation < myString.length) {
characterLocation = [myString rangeOfCharacterFromSet:newlineCharacterSet options:NSLiteralSearch range:NSMakeRange(characterLocation, (myString.length - characterLocation))].location;
if (characterLocation == NSNotFound) {
break;
}
// if we are at a r character and the next character is a n, skip the next character
if (myString.length >= characterLocation &&
[myString characterAtIndex:characterLocation] == 'r' &&
[myString characterAtIndex:characterLocation + 1] == 'n') {
characterLocation++;
}
lineCount++;
characterLocation++;
}
NSLog(@"%i", lineCount);
尝试这个
NSString * myString = @"line 1 n line 2 n";
int count = [[myString componentsSeparatedByString:@"n"] count];
NSLog(@"%d", count);
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