如何获得来自其他API回调调用的响应
我有一个短信API，我打电话来发送短信。 我传递一些json和url回调来获得响应状态，并发送短信。
之后服务器调用我的回调url，但我无法获得响应正文。 $ _GET和$ _POST为空...文档不存在。 它应该有一些JSON。 有人能帮我吗？ 提前致谢
REQUEST_URI => /dev/egoi-resp.php
GET => Array
(
)
POST => Array
(
)
SERVER => Array
(
[PATH] => /sbin:/usr/sbin:/bin:/usr/bin
[PWD] => /usr/local/cpanel/cgi-sys
[SHLVL] => 0
[SCRIPT_NAME] => /dev/egoi-resp.php
[REQUEST_URI] => /dev/egoi-resp.php
[QUERY_STRING] =>
[REQUEST_METHOD] => POST
[SERVER_PROTOCOL] => HTTP/1.1
[GATEWAY_INTERFACE] => CGI/1.1
[REMOTE_PORT] => 45721
[SCRIPT_FILENAME] => /home/nchaves/public_html/dev/egoi-resp.php
[SERVER_ADMIN] => webmaster@nunochaves.com
[CONTEXT_DOCUMENT_ROOT] => /home/nchaves/public_html
[CONTEXT_PREFIX] =>
[REQUEST_SCHEME] => http
[DOCUMENT_ROOT] => /home/nchaves/public_html
[REMOTE_ADDR] => 94.46.251.59
[SERVER_PORT] => 80
[SERVER_ADDR] => 185.11.164.13
[SERVER_NAME] => nunochaves.com
[SERVER_SOFTWARE] => Apache
[SERVER_SIGNATURE] =>
[LD_LIBRARY_PATH] => /usr/local/apache/lib
[CONTENT_LENGTH] => 166
[HTTP_CONNECTION] => close
[HTTP_HOST] => nunochaves.com
[HTTP_USER_AGENT] => Java/1.7.0_25
[HTTP_ACCEPT] => application/json
[CONTENT_TYPE] => application/json
[UNIQUE_ID] => VFeXf7kLpA0AB@tWLxMAAADG
[FCGI_ROLE] => RESPONDER
[PHP_SELF] => /dev/egoi-resp.php
[REQUEST_TIME_FLOAT] => 1415026559.7367
[REQUEST_TIME] => 1415026559
)
我有洞webhook的工作。 唯一的麻烦是在钩子被调用时修改json的答案。 我设法找到答案。
$ data = json_decode（file_get_contents（'php：// input'））;
根据文件：
url (string)
The URL that will be used for the Hook
actions (list)
The list of actions for which this hook is triggered.
Acceptable values: PROCESSED, SENT, DELIVERED, FAILED, CANCELED,
当您订阅的事件触发挂钩时，此URL将用作回调。 因此，让我们想象你订阅URL为http://foo.org/foo.php的SENT钩子。
钩子相关的数据将被发送（ POST ）到url - > http://foo.org/foo.php 。
为了查看收到的数据，我会以这个（天真的）存根作为出发点：
<?php
$f = fopen('/tmp/hook.log', 'a+');
$d = date('Y-m-d H:i:s');
fwrite($f, "------------- $d -----------n");
fwrite($f, print_r($_POST, true));
fclose($f);
?>
检查/tmp/hook.log文件（ tail -f /tmp/hook.log ）以查看正在发送的内容。
希望这有助于，关心，LL
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