mongodb: how to get the last N records?
I can't find anywhere it has been documented this. By default, the find() operation will get the records from beginning. How can I get the last N records in mongodb?
Edit: also I want the returned result ordered from less recent to most recent, not the reverse.
If I understand your question, you need to sort in ascending order.
Assuming you have some id or date field called "x" you would do ...
.sort()
db.foo.find().sort({x:1});
The 1 will sort ascending (oldest to newest) and -1 will sort descending (newest to oldest.)
If you use the auto created _id field it has a date embedded in it ... so you can use that to order by ...
db.foo.find().sort({_id:1});
That will return back all your documents sorted from oldest to newest.
Natural Order
You can also use a Natural Order mentioned above ...
db.foo.find().sort({$natural:1});
Again, using 1 or -1 depending on the order you want.
Use .limit()
Lastly, it's good practice to add a limit when doing this sort of wide open query so you could do either ...
db.foo.find().sort({_id:1}).limit(50);
or
db.foo.find().sort({$natural:1}).limit(50);
The last N added records, from less recent to most recent, can be seen with this query:
db.collection.find().skip(db.collection.count() - N)
If you want them in the reverse order:
db.collection.find().sort({ $natural: -1 }).limit(N)
If you install Mongo-Hacker you can also use:
db.collection.find().reverse().limit(N)
If you get tired of writing these commands all the time you can create custom functions in your ~/.mongorc.js. Eg
function last(N) {
return db.collection.find().skip(db.collection.count() - N);
}
then from a mongo shell just type last(N)
In order to get last N records you can execute below query:
db.yourcollectionname.find({$query: {}, $orderby: {$natural : -1}}).limit(yournumber)
if you want only one last record:
db.yourcollectionname.findOne({$query: {}, $orderby: {$natural : -1}})
Note: In place of $natural you can use one of the columns from your collection.
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