Why is this snippet compilable in C?

Possible Duplicate:
In C arrays why is this true? a[5] == 5[a]

3["zdvnngfgnfg"];

---

It's equivalent to

"zdvnngfgnfg"[3];

which is legal and means "take the address of that literal and add 3*sizeof(char) to it". Will have no effect anyway.

Also see this very similar question.

---

arr[i] is parsed as *(arr+i) which can be written as *(i+arr) and hence i[arr]
Now "strngjwdgd" is a pointer to a constant character array stored at read only location.
so it works!!

---

The string literal( array ) decays to a pointer of type char* . Then you take the fourth element:

3["zdvnngfgnfg"] == "zdvnngfgnfg"[3]

Why you can write the subscript infront of the array is another question:

In C arrays why is this true?

链接地址: http://www.djcxy.com/p/86720.html

上一篇: C中的chars [4]和4 [chars]是否相同？ 为什么？

下一篇: 为什么这个代码片段可以在C中编译？