Using GCC to produce readable assembly?
I was wondering how to use GCC on my C source file to dump a mnemonic version of the machine code so I could see what my code was being compiled into. You can do this with Java but I haven't been able to find a way with GCC.
I am trying to re-write a C method in assembly and seeing how GCC does it would be a big help.
If you compile with debug symbols, you can use objdump
to produce a more readable disassembly.
>objdump --help
[...]
-S, --source Intermix source code with disassembly
-l, --line-numbers Include line numbers and filenames in output
Example:
> gcc -g -c test.c
> objdump -d -M intel -S test.o
test.o: file format elf32-i386
Disassembly of section .text:
00000000 <main>:
#include <stdio.h>
int main(void)
{
0: 55 push ebp
1: 89 e5 mov ebp,esp
3: 83 e4 f0 and esp,0xfffffff0
6: 83 ec 10 sub esp,0x10
puts("test");
9: c7 04 24 00 00 00 00 mov DWORD PTR [esp],0x0
10: e8 fc ff ff ff call 11 <main+0x11>
return 0;
15: b8 00 00 00 00 mov eax,0x0
}
1a: c9 leave
1b: c3 ret
我想补充一下这些答案,如果你给gcc flag -fverbose-asm
,它发出的汇编器会更清晰地阅读。
Use the -S (note: capital S) switch to GCC, and it will emit the assembly code to a file with a .s extension. For example, the following command:
gcc -O2 -S foo.c
will leave the generated assembly code on the file foo.s.
Ripped straight from http://www.delorie.com/djgpp/v2faq/faq8_20.html (but removing erroneous -c
)
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