用于从字符串中提取给定类型的子字符串的正则表达式
有人可以帮我找到从字符串“Andy Joe：CT23123”中提取子串“CT23123”的正则表达式。 我需要一个正则表达式来提取'：'后面的任何内容，后面跟着两个字母（可以是大写或小写）和5位数字。
尝试这个：
/:([a-zA-Z]{2}d{5})/
r = /
(?<=:) # match a colon in a positive lookbehind
[A-Z]{2} # match two letters
d{5} # match 5 digits
(?=D|z) # match a non-digit or the end of the string in a positive lookahead
/xi # extended/free-spacing mode (x) and case-indifferent (i)
"Andy Joe :CT23123"[r] #=> "CT23123"
"Andy Joe:CT23123a"[r] #=> "CT23123"
"Andy Joe:CT231234"[r] #=> nil
要么：
r = /
: # match a colon
([A-Z]{2}d{5}) # match two letters followed by 5 digits in capture group 1
(?:D|z) # match a non-digit or the end of the string in a non-capture group
/xi # extended/free-spacing mode (x) and case-indifferent (i)
"Andy Joe :CT23123"[r,1] #=> "CT23123"
"Andy Joe:CT23123a"[r,1] #=> "CT23123"
"Andy Joe:CT231234"[r,1] #=> nil
使用不区分大小写选项的另一个版本：
/:([a-z]{2}d{5})/i
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