jQuery x y document coordinates of DOM object

I need to get the X,Y coordinates (relative to the document's top/left) for a DOM element. I can't locate any plugins or jQuery property or method that can give these to me. I can get the top and left of the DOM element, but that can be either relative to its current container/parent or to document.

---

you can use Dimensions plugin [Deprecated... included in jQuery 1.3.2+]

offset()
Get the current offset of the first matched element, in pixels, relative to the document .

position()
Gets the top and left position of an element relative to its offset parent .

knowing this, then it's easy... (using my little svg project as an example page)

var x = $("#wrapper2").offset().left;
var y = $("#wrapper2").offset().top;

console.log('x: ' + x + ' y: ' + y);

output:

x: 53 y: 177

hope it helps what you're looking for.

here's an image of offset() and position()

using XRay

using Web Developer toolbar

---

My solution is a plugin with "workarounds" :+D . But Works!

jQuery.fn.getPos = function(){
        var o = this[0];
        var left = 0, top = 0, parentNode = null, offsetParent = null;
        offsetParent = o.offsetParent;
        var original = o;
        var el = o;
        while (el.parentNode != null) {
            el = el.parentNode;
            if (el.offsetParent != null) {
                var considerScroll = true;
                if (window.opera) {
                    if (el == original.parentNode || el.nodeName == "TR") {
                        considerScroll = false;
                    }
                }
                if (considerScroll) {
                    if (el.scrollTop && el.scrollTop > 0) {
                        top -= el.scrollTop;
                    }
                    if (el.scrollLeft && el.scrollLeft > 0) {
                        left -= el.scrollLeft;
                    }
                }
            }            
            if (el == offsetParent) {
                left += o.offsetLeft;
                if (el.clientLeft && el.nodeName != "TABLE") {
                    left += el.clientLeft;
                }
                top += o.offsetTop;
                if (el.clientTop && el.nodeName != "TABLE") {
                    top += el.clientTop;
                }
                o = el;
                if (o.offsetParent == null) {
                    if (o.offsetLeft) {
                        left += o.offsetLeft;
                    }
                    if (o.offsetTop) {
                        top += o.offsetTop;
                    }
                }
                offsetParent = o.offsetParent;
            }
        }
        return {
            left: left,
            top: top
        };
    };

Usage:

var p = $("#wrapper2").getPos();
alert("top:"+p.top+"; left:"+p.left);

---

The offset function will do that for you.

Here is the example they give:

var p = $("p:last");
var offset = p.offset();
p.html( "left: " + offset.left + ", top: " + offset.top );

链接地址: http://www.djcxy.com/p/88588.html

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