在Internet Explorer和多个监视器中的Window.screen

我有一个具有不同屏幕分辨率的双显示器设置,当我在Chrome中访问此页面时,它显示了两个屏幕的正确解决方案。 但IE只显示我的主屏幕的分辨率。 它比在IE中显示window.screen.availWidthwindow.screen.availHeight只返回主屏幕的值。 我可以获得运行Internet Explorer的第二个屏幕的屏幕分辨率吗?


使用http://archive.cpradio.org/code/javascript/dual-monitors-and-windowopen/上的古代代码

function FindLeftWindowBoundry()
{
	// In Internet Explorer window.screenLeft is the window's left boundry
	if (window.screenLeft)
	{
		return window.screenLeft;
	}
	
	// In Firefox window.screenX is the window's left boundry
	if (window.screenX)
		return window.screenX;
		
	return 0;
}

window.leftWindowBoundry = FindLeftWindowBoundry;

// Find Left Boundry of the Screen/Monitor
function FindLeftScreenBoundry()
{
	// Check if the window is off the primary monitor in a positive axis
	// X,Y                  X,Y                    S = Screen, W = Window
	// 0,0  ----------   1280,0  ----------
	//     |          |         |  ---     |
	//     |          |         | | W |    |
	//     |        S |         |  ---   S |
	//      ----------           ----------
	if (window.leftWindowBoundry() > window.screen.width)
	{
		return window.leftWindowBoundry() - (window.leftWindowBoundry() - window.screen.width);
	}
	
	// Check if the window is off the primary monitor in a negative axis
	// X,Y                  X,Y                    S = Screen, W = Window
	// 0,0  ----------  -1280,0  ----------
	//     |          |         |  ---     |
	//     |          |         | | W |    |
	//     |        S |         |  ---   S |
	//      ----------           ----------
	// This only works in Firefox at the moment due to a bug in Internet Explorer opening new windows into a negative axis
	// However, you can move opened windows into a negative axis as a workaround
	if (window.leftWindowBoundry() < 0 && window.leftWindowBoundry() > (window.screen.width * -1))
	{
		return (window.screen.width * -1);
	}
	
	// If neither of the above, the monitor is on the primary monitor whose's screen X should be 0
	return 0;
}

window.leftScreenBoundry = FindLeftScreenBoundry;

console.log(window.screen.width);
console.log(window.leftScreenBoundry());

console.log(window.screen.height);
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