将参数列表传递给Python函数
这个问题在这里已经有了答案：
some_list = ["some", "values", "in", "a", "list", ]
func(*some_list)
这相当于：
func("some", "values", "in", "a", "list")
固定的x参数可能需要考虑：
func(5, *some_list)
...相当于：
func(5, "some", "values", "in", "a", "list")
如果你没有指定x值（在上面的例子中是5 ），那么some_list第一个值将作为x参数传递给func 。
将值传递为逗号分隔值
>>> def func(x, *p): # p is stored as tuple
... print "x =",x
... for i in p:
... print i
... return p
...
>>> print func(1,2,3,4) # x value 1, p takes the rest
x = 1
2
3
4
(2,3,4) # returns p as a tuple
您可以通过阅读文档了解更多信息
链接地址: http://www.djcxy.com/p/9063.html上一篇: Passing a list of parameters into a Python function
下一篇: what does double star followed by variable name mean in python?