How to generate a new GUID?

I'm working on a web service which requires a new GUID() passed as a reference to a method within the service.

I am not familiar with C# or the GUID() object , but require something similar for PHP (so create a new object which from my understanding returns an empty/blank GUID ).

Any ideas?

---

You can try the following:

function GUID()
{
    if (function_exists('com_create_guid') === true)
    {
        return trim(com_create_guid(), '{}');
    }

    return sprintf('%04X%04X-%04X-%04X-%04X-%04X%04X%04X', mt_rand(0, 65535), mt_rand(0, 65535), mt_rand(0, 65535), mt_rand(16384, 20479), mt_rand(32768, 49151), mt_rand(0, 65535), mt_rand(0, 65535), mt_rand(0, 65535));
}

Source - com_create_guid

---

As an alternative to the above options:

$guid = bin2hex(openssl_random_pseudo_bytes(16));

It gives a string like 412ab7489d8b332b17a2ae127058f4eb

---

<?php
function guid(){
if (function_exists('com_create_guid') === true)
    return trim(com_create_guid(), '{}');

$data = openssl_random_pseudo_bytes(16);
$data[6] = chr(ord($data[6]) & 0x0f | 0x40);
$data[8] = chr(ord($data[8]) & 0x3f | 0x80);
return vsprintf('%s%s-%s-%s-%s-%s%s%s', str_split(bin2hex($data), 4));
}
?>

GUID生成器

链接地址: http://www.djcxy.com/p/91436.html

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