我怎样才能有一个Django信号调用模型方法？
也许这只是晚了，但我不明白为什么这不起作用。 当我有一个post_save信号调用一个通用函数时，它可以工作，但是当我有一个post_save信号从模型中调用一个方法时，什么都不会发生。 这是可以工作的代码：
class Revision(models.Model):
# Model junk...
def send_email(sender, instance, created, **kwargs):
if created:
print "DO STUFF"
signals.post_save.connect(send_email, sender=Revision)
但是这不起作用：
class Revision(models.Model):
# Model junk...
def send_email(sender, instance, created, **kwargs):
if created:
print "DO STUFF"
signals.post_save.connect(Revision.send_email, sender=Revision)
那里有一个善良的灵魂，能让我不用把头撞到墙上？ 谢谢。
在我看来，第二个问题是你正在使用无限制的send_mail方法。 如果你真的想从一个类中调用send_mail ， @classmethod或@staticmethod可以帮助你：
class Revision(models.Model):
# Model junk...
@classmethod
def send_email(cls, sender, instance, created, **kwargs):
if created:
print "DO STUFF"
signals.post_save.connect(Revision.send_email, sender=Revision)
要么
class Revision(models.Model):
# Model junk...
@staticmethod
def send_email(sender, instance, created, **kwargs):
if created:
print "DO STUFF"
signals.post_save.connect(Revision.send_email, sender=Revision)
另外，如果不使用这些装饰器，则可以传递有界的实例方法：
class Revision(models.Model):
# Model junk...
def send_email(self, sender, instance, created, **kwargs):
if created:
print "DO STUFF"
signals.post_save.connect(Revision().send_email, sender=Revision)
参考文献：
从Django源代码：
def connect(self, receiver, sender=None, weak=True, dispatch_uid=None):
"""
Connect receiver to sender for signal.
Arguments:
receiver
A function or an instance method which is to receive signals.
Receivers must be hashable objects.
If weak is True, then receiver must be weak-referencable (more
precisely saferef.safeRef() must be able to create a reference
to the receiver).
Receivers must be able to accept keyword arguments.
If receivers have a dispatch_uid attribute, the receiver will
not be added if another receiver already exists with that
dispatch_uid.
@classmethod和@staticmethod之间的@classmethod ：Python中的@classmethod和@staticmethod什么区别？