Regular expression which matches a pattern, or is an empty string
I have the following Regular Expression which matches an email address format:
^[w.-]+@([w-]+.)+[a-zA-Z]+$
This is used for validation with a form using JavaScript. However, this is an optional field. Therefore how can I change this regex to match an email address format, or an empty string?
From my limited regex knowledge, I think b
matches an empty string, and |
means "Or", so I tried to do the following, but it didn't work:
^[w.-]+@([w-]+.)+[a-zA-Z]+$|b
To match pattern
or an empty string, use
^$|pattern
Explanation
^
and $
are the beginning and end of the string anchors respectively. |
is used to denote alternates, eg this|that
. References
On b
b
in most flavor is a "word boundary" anchor. It is a zero-width match, ie an empty string, but it only matches those strings at very specific places, namely at the boundaries of a word.
That is, b
is located:
w
and W
(either order): ^
and w
w
w
and $
w
References
On using regex to match e-mail addresses
This is not trivial depending on specification.
Related questions
An alternative would be to place your regexp in non-capturing parentheses. Then make that expression optional using the ?
qualifier, which will look for 0 (ie empty string) or 1 instances of the non-captured group.
For example:
/(?: some regexp )?/
In your case the regular expression would look something like this:
/^(?:[w.-]+@([w-]+.)+[a-zA-Z]+)?$/
No |
"or" operator necessary!
Here is the Mozilla documentation for JavaScript Regular Expression syntax.
I'm not sure why you'd want to validate an optional email address, but I'd suggest you use
^$|^[^@s]+@[^@s]+$`
meaning
^$ empty string
| or
^ beginning of string
[^@s]+ any character but @ or whitespace
@
[^@s]+
$ end of string
You won't stop fake emails anyway, and this way you won't stop valid addresses.
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