How to process python generated error messages my own way?
For some code as follows,
opts, args = getopt.getopt(sys.argv[1:], "c:", ...
for o,v in opts:
...
elif o in ("-c", "--%s" % checkString):
kCheckOnly = True
clientTemp = v
If I don't give the parameter after the -c, I get the error messages as follows.
Traceback (most recent call last):
File "niFpgaTimingViolationMain.py", line 100, in
opts, args = getopt.getopt(sys.argv[1:], "hdc:t:",[helpString, debugString, checkString, twxString])
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/getopt.py", line 91, in getopt
opts, args = do_shorts(opts, args[0][1:], shortopts, args[1:])
File "/System/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/getopt.py", line 195, in do_shorts
opt)
getopt.GetoptError: option -c requires argument
Is there any way to catch this error, and process it to print something like this? It seems that just wrapping the code in try/except doesn't work.
ERROR: You forgot to give the file name after -c option
您可以捕获getopt.GetoptError并自己检查'opt'和'msg'属性：
try:
opts, args = getopt.getopt(sys.argv[1:], "c:", ...
except getopt.GetoptError, e:
if e.opt == 'c' and 'requires argument' in e.msg:
print >>sys.stderr, 'ERROR: You forgot to give the file name after -c option'
sys.exit(-1)
正确的答案是使用OptionParser模块，而不是试图“滚动你自己的”。
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