我将首先解释我的问题的当前情况。

楷模

例如有5个模型： Community ， User ， Membership ， Reservation ， Item

class User(Model):
    name = CharField(max_length=50)
    communities = ManyToManyField('Community', through='Membership')


class Community(Model):
    name = CharField(max_length=50)


class Membership(Model):
    user = ForeignKey('User')
    community = ForeignKey('Community')


class Item(Model):
    name = CharField(max_length=50)


class Reservation(Model):
    item = ForeignKey('Item')
    membership = ForeignKey('Membership')

Community是m：m User通过Membership 。

Reservation是1：m Membership

Item是1：m Reservation

ModelSerializer

class ReservationSerializer(ModelSerializer):
    class Meta:
        model = Reservation
        fields = ('membership', 'item')

问题

从request.user自动设置User值的最佳方法是什么？因此，此ReservationSerializer所需的属性只是community和item而不是membership和item ？

参考

如何使用DRF的ModelSerializer创建一个django用户

用Django Rest Framework返回当前用户

http://www.django-rest-framework.org/tutorial/4-authentication-and-permissions#associating-snippets-with-users

Django Rest框架ModelSerializer在create上设置属性

动态限制相关字段的查询集

djangorestframework：在相关字段中过滤

---

序列化器的作用是以清晰的方式表示信息，而不是操纵这些数据。 您可能希望在视图上执行此操作：使用DRF上可用的通用ListCreateAPIView，可以使用pre_save信号来存储该信息：

from rest_framework.generics import ListCreateAPIView

class ReservationView(ListCreateAPIView):
    def pre_save(self, obj):
        obj.membership.user = self.request.user

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