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Scanner is skipping nextLine() after using next() or nextFoo()? 15 answers

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You have to clear your Scanner so you can use reader.nextLine(); , like this :

if (input % 2 == 0) {
    System.out.println("The input was even");
} else if (input % 2 == 1) {
    System.out.println("The input was odd");
} else {
    System.out.println("The input was not an integer");
}


reader.nextLine();//<<--------------Clear your Scanner so you can read the next input


//example with user string input
System.out.println("Verify by typing the word 'FooBar': ");
String input2 = reader.nextLine();
System.out.println("The string equal 'FooBar': " + input2.equals("FooBar"));

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Edit

why does 'next()' ignore the n still left in the scanner?

You will understand with this example here :

next()

public static void main(String[] args) {
    String str = "Hello World! Hello Java!";

    // create a new scanner with the specified String Object
    Scanner scanner = new Scanner(str);

    while(scanner.hasNext()){
        System.out.println( scanner.next());
    }
    scanner.close();
}

Output

Hello
World!
Hello
Java!

nextLine()

public static void main(String[] args) {
    String str = "Hello World!nHello Java!";

    // create a new scanner with the specified String Object
    Scanner scanner = new Scanner(str);

    while(scanner.hasNext()){
        System.out.println( scanner.nextLine());
    }
    scanner.close();
}

Output

Hello World!
Hello Java!

So we can understand that next() read word by word so it does not use n like nextLine()

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