Is there a way to distinguish if a script was invoked from the command line or by the web server? ( See What is the canonical way to determine commandline vs. http execution of a PHP script? for best answer and more detailed discussion - didn't find that one before posting) I have a (non-production) server with Apache 2.2.10 and PHP 5.2.6. On it, in a web-accessible directory is my PHP s
有没有办法区分脚本是从命令行还是由Web服务器调用？ （ 请参阅什么是确定PHP脚本的命令行与http执行的规范方法？以获得最佳答案和更详细的讨论 - 在发布前没有找到该方法） 我有一个（非生产）服务器与Apache 2.2.10和PHP 5.2.6。 在它上面，在一个web访问目录中是我的PHP脚本maintenance_tasks.php 。 我想从命令行或通过HTTP请求（通过在浏览器中打开）调用此脚本。 是否有一些变量允许我可靠地确定脚本如何被调用？
I've seen some PHP statements that go something like if($variable) {} or if(function()) {} (if statements that don't compare two variables) and I know they roughly mean if a function executes or if this variable exists but I can't seem to find any information on how they work specifically. Can anybody shed some light on this? if(function()) {}表示函数函数的返回值是真还是假，则块将
我见过一些PHP语句就像这样 if($variable) {} or if(function()) {} (if statements that don't compare two variables) 我知道它们大致意味着如果一个函数执行或者这个变量存在但我似乎无法找到任何有关它们如何工作的信息。 任何人都可以对此有所了解吗？ if(function()) {}表示函数函数的返回值是真还是假，则块将执行。 从PHP手册： 如果（expr）语句 如关于表达式的部分所述，expression被评估为其布尔值。 如
I'm trying to do a chat system, I'm having troubles with it, my ideia is the following: When the user send a message, this message has to be saved in 2 tables in my database... But it isn't working, the message is saving in only one table. public function sendMessage() $data = $this->request->data(); $sessionId = $data['idSession']; $userId = $this->request-&
我试图做一个聊天系统，我遇到了麻烦，我的理念如下： 当用户发送消息时，该消息必须保存在我的数据库中的两个表中......但它不起作用，消息只保存在一个表中。 公共职能sendMessage（） $data = $this->request->data(); $sessionId = $data['idSession']; $userId = $this->request->session()->read('Auth.User.id'); $msg = $data['message']; $typeMessage = $data['type']; $m
One of the classes at school is a CakePHP class and there one question no one has been able to answer and that is a way of blocking users from accessing certain things(like the admin pages). The way I did was just using a PHP statement in the View for a certain index.ctp page that said If the role was = 1 then shows this HTML else show this other HTML. But that's not really the right away.
其中一个课程是CakePHP课程，有一个问题没有人能够回答，这是阻止用户访问某些内容（如管理页面）的一种方式。 我做的方式只是在View中使用PHP语句来表示某个index.ctp页面，如果该角色为= 1，那么将显示此HTML，否则显示其他HTML。 但这并不是马上就会。 因此，我设置了管理路由前缀，并重新烘焙了具有路由的MVC文件，但不知道如何阻止用户使用角色“1” - 意味着默认情况下访问管理员前缀页面。 也许我失去了一些东西......
CakePHP 3.0 I'm getting a "Missing Route" error for a route that exists. Here are my routes: #my admin routes... Router::prefix('admin', function($routes) { $routes->connect('/', ['controller'=>'Screens', 'action'=>'index']); $routes->connect('/screens', ['controller'=>'Screens', 'action'=>'index']); $routes->connect('/screens/index', ['controll
CakePHP 3.0 对于存在的路由，我收到“Missing Route”错误。 这是我的路线： #my admin routes... Router::prefix('admin', function($routes) { $routes->connect('/', ['controller'=>'Screens', 'action'=>'index']); $routes->connect('/screens', ['controller'=>'Screens', 'action'=>'index']); $routes->connect('/screens/index', ['controller'=>'Screens', 'action'=>'ind
Sorry for being a bit of a dumb-ass but I'm trying to learn and have been looking at this for a couple of days but I'm still not completely sure how it works. I'm following an offline tutorial about using prefixes. the tutorial says do this: 1 - uncomment the admin routing prefix in core.php 2 - add the following to users_controller.php: public function dashboard() { $ro
对不起，有点愚蠢的屁股，但我试图学习，并一直在看这几天，但我仍然不完全确定它是如何工作的。 我正在关注使用前缀的离线教程。 本教程说明了这一点：1 - 取消注释core.php中的管理路由前缀 2 - 将以下内容添加到users_controller.php： public function dashboard() { $role = $this->Auth->user('role'); if (!empty($role)) { $this->redirect(array($role=>true, 'act
Because of the Twitter API 1.0 retirement as of June 11th 2013, the script below does not work anymore. // Create curl resource $ch = curl_init(); // Set url curl_setopt($ch, CURLOPT_URL, "http://twitter.com/statuses/user_timeline/myscreenname.json?count=10"); // Return the transfer as a string curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // $output contains the output string $output = cu
由于截至2013年6月11日Twitter API 1.0退役，下面的脚本不再适用。 // Create curl resource $ch = curl_init(); // Set url curl_setopt($ch, CURLOPT_URL, "http://twitter.com/statuses/user_timeline/myscreenname.json?count=10"); // Return the transfer as a string curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // $output contains the output string $output = curl_exec($ch); // Close curl resource to
I started by googling, and found this article which talks about mutex tables. I have a table with ~14 million records. If I want to add more data in the same format, is there a way to ensure the record I want to insert does not already exist without using a pair of queries (ie, one query to check and one to insert is the result set is empty)? Does a unique constraint on a field guarantee the
我开始用google搜索，并找到了这篇谈论互斥表的文章。 我有一张约有1400万条记录的表格。 如果我想以相同的格式添加更多的数据，有没有办法确保我想插入的记录不存在，而不使用一对查询（即，一个查询来检查，一个要插入的结果集是空）？ 一个字段上的唯一约束是否保证插入将会失败，如果它已经在那里？ 似乎只有一个约束，当我通过php发布插入时，脚本就会呱呱叫。 一个字段上的唯一约束是否保证插入将会失败，如果它
I'm using type hinting in PhpStorm in .php files which works fine. I can do type hinting for php fragments <? ?> <? ?> in .html files for variables and for $this like: <? /** * @var $this My_Custom_Class */ ?> I have some dynamically added properties in .html templates, which I don't know how should I instruct PhpStorm to hint. Config file containing associative arr
我在PhpStorm中使用.php文件中的类型提示工作正常。 我可以为php碎片进行类型提示<? ?> <? ?> .html文件中的变量和$this这样的： <? /** * @var $this My_Custom_Class */ ?> 我在.html模板中有一些动态添加的属性，我不知道应该如何指示PhpStorm提示。 包含关联数组的配置文件被传递给init方法，然后像下面这样创建属性： public function init($params) { foreach ($params as $key => $value)
PHPDoc provides the @var tag, which should work even for variables declared outside of a class. However, this does not seem to work if I define the variable as a magic member of an object: /** @var $app->translator FortressMessageTranslator */ $app->translator = new FortressMessageTranslator(); Where $app is a Slim object that supports arbitrary property assignment via magic setters and
PHPDoc提供了@var标签，即使对于在类之外声明的变量，它也应该可以工作。 但是，如果我将变量定义为对象的魔术成员，这似乎不起作用： /** @var $app->translator FortressMessageTranslator */ $app->translator = new FortressMessageTranslator(); 其中$app是一个Slim对象，通过魔法设置器和getter支持任意属性分配。 我知道我可以通过@property标记将它添加到Slim ，但是每次创建新属性时都需要更改核心Slim代码