我很确定它可能（或）导致它可能太多了。 $filechk1 = "/temp/files/" . $data[0] . ".doc"; $filechk2 = "/temp/files/" . $data[1] . ".doc"; $dirchk1 = "/temp/files/" . $batchid . "/" .$data[0] . ".doc"; $dirchk2 = "/temp/files/" . $batchid . "/" . $data[1] . ".doc"; if(is_file($filechk1) && (is_file($filechk2))) || (is_file($dirchk1) && (is_file($dirchk2))){ ... } Incorrectly plac
我很确定它可能（或）导致它可能太多了。 $filechk1 = "/temp/files/" . $data[0] . ".doc"; $filechk2 = "/temp/files/" . $data[1] . ".doc"; $dirchk1 = "/temp/files/" . $batchid . "/" .$data[0] . ".doc"; $dirchk2 = "/temp/files/" . $batchid . "/" . $data[1] . ".doc"; if(is_file($filechk1) && (is_file($filechk2))) || (is_file($dirchk1) && (is_file($dirchk2))){ ... } 错误放置圆括号
I keep getting the following error: Parse error: syntax error, unexpected T_SL in /home/a4999406/public_html/willingLog.html on line 70 on the following code (first line is line 70): echo <<<END <form action = "willingLog.html" method="post"><pre> First <input type="text" name="first" /> Last <input type="text" name="last" />
我不断收到以下错误： 解析错误：语法错误，第70行/home/a4999406/public_html/willingLog.html中的意外T_SL 在下面的代码中（第一行是第70行）： echo <<<END <form action = "willingLog.html" method="post"><pre> First <input type="text" name="first" /> Last <input type="text" name="last" /> Email <input type="text" name="email
I'm getting a Parse error: syntax error, unexpected T_DOUBLE_ARROW PHP on line 47, which is 'post_content' => $thisShow['content'], Anyone got any ideas why? protected function _saveShow($thisShow) { $saveData = array( 'mid' => $this->_saveAsUserId, 'post_title' => $thisShow['title'], 'post_name' => slug($thisShow['title'],
我得到了一个 Parse error: syntax error, unexpected T_DOUBLE_ARROW PHP on line 47, which is 'post_content' => $thisShow['content'], 任何人有任何想法为什么？ protected function _saveShow($thisShow) { $saveData = array( 'mid' => $this->_saveAsUserId, 'post_title' => $thisShow['title'], 'post_name' => slug($thisShow['title'],
The code below is part of an rss feed parser using WordPress's simplepie fetch_feed()... Code is: if ($enclosure = $item->get_enclosure(0)) { $image_thumb = $item->get_enclosure()->get_link().'screenshot.jpg'; $image = $item->get_enclosure()->get_link().'screenshot-full.jpg'; } $link = esc_url( strip_tags( $item->get_link() ) ); $content = $ite
下面的代码是使用WordPress的simplepie fetch_feed（）的rss feed解析器的一部分... 代码是： if ($enclosure = $item->get_enclosure(0)) { $image_thumb = $item->get_enclosure()->get_link().'screenshot.jpg'; $image = $item->get_enclosure()->get_link().'screenshot-full.jpg'; } $link = esc_url( strip_tags( $item->get_link() ) ); $content = $item->get_cont
T_PAAMAYIM_NEKUDOTAYIM sounds really exotic, but most certainly absolutely nonsense to me. I traced it all down to this lines of code: <?php Class Context { protected $config; public function getConfig($key) { // Here's the problem somewhere... $cnf = $this->config; return $cnf::getConfig($key); } function __construct() { $this->config = new Config();
T_PAAMAYIM_NEKUDOTAYIM听起来真的很奇特，但对我来说绝对是无稽之谈。 我将其追溯到这些代码行： <?php Class Context { protected $config; public function getConfig($key) { // Here's the problem somewhere... $cnf = $this->config; return $cnf::getConfig($key); } function __construct() { $this->config = new Config(); } } ?> 在构造函数中，我创建了一个Confi
<? switch($data['type']) : ?> <? case 'log': ?> <? while ($row = $data['loop']->fetch()) : ?> <table class="t-errors"> <tr> <td> <b>IP:</b> <? echo $row['LogShellIP']; ?> <b>Command:</b> <? echo $row['LogShellCommand']; ?> &
<? switch($data['type']) : ?> <? case 'log': ?> <? while ($row = $data['loop']->fetch()) : ?> <table class="t-errors"> <tr> <td> <b>IP:</b> <? echo $row['LogShellIP']; ?> <b>Command:</b> <? echo $row['LogShellCommand']; ?> &
I have a certain piece of code that I'm trying to use with PHP Version 5.2.14 . Is it incompatible?? I run the following, jailshell-3.2$ php -l /XYZ/functions.php And it gives: Parse error: syntax error, unexpected T_FUNCTION, expecting ')' in /XYZ/functions.php on line 2115 Errors parsing /XYZ/functions.php The code is: 2114 $range = array_map( 2115 functio
我有一段代码，我试图使用PHP版本5.2.14。 它不兼容？ 我运行以下， jailshell-3.2$ php -l /XYZ/functions.php 它给出了： 解析错误：语法错误，意外的T_FUNCTION，期望'）'在2115行的/XYZ/functions.php错误解析/XYZ/functions.php 代码是： 2114 $range = array_map( 2115 function (DatePeriod $p) use ($vt2) { 2116 $res = array(); 您的代码使用PHP 5.3支持的anonymou
Possible Duplicate: mysql_fetch_array() expects parameter 1 to be resource, boolean given in select Warning: mysql_fetch_* expects parameter 1 to be resource, boolean given error Not much to explain. I am using the code listed above and getting the error listed below. I am pretty clueless about what this error means and would love an explanation. Warning: mysql_fetch_array() expects par
可能重复： mysql_fetch_array（）期望参数1是资源，布尔在select中给出 警告：mysql_fetch_ *期望参数1是资源，布尔给定错误 没有太多解释。 我正在使用上面列出的代码并获取下面列出的错误。 我对这个错误意味着什么并且会喜欢解释非常无知。 警告：mysql_fetch_array（）期望参数1是资源，布尔值在...中给出 $query = "SELECT id FROM table WHERE user!= '$username' AND reviewed i
I have this class ZghFEBundleEntityUser which extends FOSUserBundleModelUser . use FOSUserBundleModelUser as BaseUser; class User extends BaseUser implements ParticipantInterface { use BasicInfo; // .. } And BaseUser class: abstract class User implements UserInterface, GroupableInterface { protected $id; // .. } And BaseInfo trait: trait BasicInfo { /** * @ORMColumn
我有这个类ZghFEBundleEntityUser ，它扩展了FOSUserBundleModelUser 。 use FOSUserBundleModelUser as BaseUser; class User extends BaseUser implements ParticipantInterface { use BasicInfo; // .. } 和BaseUser类： abstract class User implements UserInterface, GroupableInterface { protected $id; // .. } 和BaseInfo特性： trait BasicInfo { /** * @ORMColumn(type="string", len
How to resolve a property name conflict when a class uses two Traits with homonymous properties ? Example: <?php trait Video { public $name = 'v'; } trait Audio { public $name = 'a'; } class Media { use Audio, Video; } $media = new Media(); $media->name; I've tried insteadof (Video::name insteadof Audio) and (Video::name as name2) without success. Thanks in adva
当一个类使用具有同名属性的两个Traits时如何解决属性名称冲突？ 例： <?php trait Video { public $name = 'v'; } trait Audio { public $name = 'a'; } class Media { use Audio, Video; } $media = new Media(); $media->name; 我试过（视频::名称而不是音频）和（视频::名称为name2），但没有成功。 提前致谢 ！ 你不能，仅限于它的方法。 但是，只有当值相同时，它们才可以使用相同的属