Error posting message with link to Facebook

We are trying to post from PHP to a Facebook, we are using HybridAuth but the question is not related to it. What works: -posting to user profile, works fine,including when using picture and link -posting to page works including image(but not with link) What does not work -posting to page when we set a link(the url is not the issue since it works posting it to user profile ) The error is a gen

错误张贴消息与链接到Facebook

我们正试图从PHP发布到Facebook,我们使用的是HybridAuth,但问题与它无关。 什么工作: - 发布到用户配置文件,工作正常,包括使用图片和链接时 - 包括图片在内的页面作品发布(但不包括链接)什么是不工作 - 当我们设置链接时发布到页面(url不是问题,因为它的工作发布到用户配置文件) 这个错误是一个通用的错误,根本没有任何帮助,谢谢Facebook开发者给我们猜测错误的麻烦 {"error":{"message":"An unknown error has o

start() takes VERY LONG TIME

Mys site works very slowly (and I didn't have any idea about why). It is based on Zend Application, I used to make about tens of such sites, so I'm sure that MY code is OK. I installed xdebugger on server, tried to profile it and guess what? php::session_start() took 48.675 seconds. Fourty Eight and a Half Seconds! It's unbelievable! What could be the reason of this? It's

start()需要很长时间

Mys网站的工作速度非常缓慢(我对此没有任何想法)。 它基于Zend Application,我曾经制作过大约几十个这样的网站,所以我确信我的代码是可以的。 我在服务器上安装了xdebugger,试图分析它并猜测是什么? php :: session_start()花了48.675秒。 四十八点五秒! 这太不可思议了! 这可能是什么原因? 这是常见的操作,为什么它可以执行很长时间? 如何解决这种行为,配置编辑? 搜索谷歌,但没有找到好的答案(几乎

Roman Numeral to integer function

basically i am trying to create a function that will turn a Roman numeral into a integer. I have an array: $roman_numerals=[ 'M' => 1000, 'CM' => 900, 'D' => 500, 'CD' => 400, 'C' => 100, 'XC' => 90, 'L' => 50, 'XL' => 40, 'X' => 10, 'IX' => 9, 'V' => 5, 'IV' => 4, 'I' => 1 ]; I'm fairly new

罗马数字到整数函数

基本上我试图创建一个函数,将罗马数字变成一个整数。 我有一个数组: $roman_numerals=[ 'M' => 1000, 'CM' => 900, 'D' => 500, 'CD' => 400, 'C' => 100, 'XC' => 90, 'L' => 50, 'XL' => 40, 'X' => 10, 'IX' => 9, 'V' => 5, 'IV' => 4, 'I' => 1 ]; 我对PHP相当陌生,所以我仍然习惯于思考的方式,所以请记住,我

Php recursion to get all possibilities of strings

Here is my code to get all possibilities: $seq[1] = 'd'; $seq[2] = 'f'; $seq[3] = 'w'; $seq[4] = 's'; for($i = 1; $i < 5; $i++) { $s['length_1'][] = $seq[$i]; $c1++; for($i2 = $i+1; $i2 < 5; $i2++) { $s['length_2'][] = $seq[$i].$seq[$i2]; $last = $seq[$i].$seq[$i2]; $c2++; for($i3 = $i2+1; $i3 < 5; $i3++) { $s['le

Php递归获得所有可能的字符串

这是我的代码来获得所有可能性: $seq[1] = 'd'; $seq[2] = 'f'; $seq[3] = 'w'; $seq[4] = 's'; for($i = 1; $i < 5; $i++) { $s['length_1'][] = $seq[$i]; $c1++; for($i2 = $i+1; $i2 < 5; $i2++) { $s['length_2'][] = $seq[$i].$seq[$i2]; $last = $seq[$i].$seq[$i2]; $c2++; for($i3 = $i2+1; $i3 < 5; $i3++) { $s['length_3'][]

Does orphanRemoval bypass onDelete?

Assume that we have two entities ( Profile and Address ). A profile can have many addresses. In that case we have: Profile: ... fields: ... oneToMany: addresses: targetEntity: Address mappedBy: profile orphanRemoval: true Address: ... fields: ... manyToOne: profile: targetEntity: Profile

orphanRemoval是否绕过了删除?

假设我们有两个实体( Profile和Address )。 配置文件可以有很多地址。 在这种情况下,我们有: Profile: ... fields: ... oneToMany: addresses: targetEntity: Address mappedBy: profile orphanRemoval: true Address: ... fields: ... manyToOne: profile: targetEntity: Profile inversedBy: ad

Is there an easy way to convert a number to a word in PHP?

In PHP, is there an easy way to convert a number to a word? For instance, 27 to twenty-seven. 我在网上找到了一些(2007/2008)源代码,因为它是版权的,但是我可以自由使用它并修改它,所以我把它放在这里并在CC-Wiki下重新许可: <?php /** * English Number Converter - Collection of PHP functions to convert a number * into English text. * * This exact code is licensed un

有没有一种简单的方法将数字转换为PHP中的单词?

在PHP中,是否有将数字转换为单词的简单方法? 例如,27日至27日。 我在网上找到了一些(2007/2008)源代码,因为它是版权的,但是我可以自由使用它并修改它,所以我把它放在这里并在CC-Wiki下重新许可: <?php /** * English Number Converter - Collection of PHP functions to convert a number * into English text. * * This exact code is licensed under CC-Wiki on Stackoverflow.

Switch/Case without a `break`, doesn't check the cases properly

I'm having trouble with a switch case conidtion. Why in the following scenario: $category = "A"; $offer = "none"; $discount = "none"; For the following code: switch (TRUE) { case ($category == 'A') : / #1 $msg = "hello"; case ($offer == 'special') : / #2 $id = "123"; case ($discount == '50D') : / #3 $id = "999"; break; echo $id; } I get output of 999 for

没有“break”的开关/外壳,不能正确检查外壳

我遇到了开关盒conidtion的问题。 为什么在以下情况下: $category = "A"; $offer = "none"; $discount = "none"; 对于下面的代码: switch (TRUE) { case ($category == 'A') : / #1 $msg = "hello"; case ($offer == 'special') : / #2 $id = "123"; case ($discount == '50D') : / #3 $id = "999"; break; echo $id; } 尽管#2和#3没有满足,我获得999输出为id ,尽管? 编辑: 例

Google image search API

I have a website where users can submit pictures. I'd like to search Google automatically with these images to minimise the chance that the pictures are stolen from an other website. I know about the Firefox extension, but that requires me right-clicking every picture and waiting for the result to appear. I'd like to automate this. I was looking for an API, but the Google Image Seach

Google图片搜索API

我有一个网站,用户可以提交图片。 我想自动搜索这些图片,以最大限度地减少图片从其他网站被盗的机会。 我知道Firefox扩展,但这需要我右键单击每张图片并等待显示结果。 我想自动执行此操作。 我一直在寻找一个API,但Google Image Seach API(https://developers.google.com/image-search/)明确提到它已被弃用。 我还找到了一个Google Custom Search API,但这似乎是为那些想要搜索他们自己的网站(这不是我正在寻找的

Force a class implementing the interface to define a constant

I am willing to force my classes to define a constant named COMMAND. If php would allow overriding constants from interfaces in would look like class RequestInterface { const COMMAND = "no-command-specified"; } class LoginRequest implements RequestInterface { const COMMAND = "loginuser"; public $username; public $password; } $request = new LoginRequest(); $request->username

强制实现接口的类定义常量

我愿意强制我的类定义一个名为COMMAND的常量。 如果PHP允许覆盖接口中的常量,看起来像 class RequestInterface { const COMMAND = "no-command-specified"; } class LoginRequest implements RequestInterface { const COMMAND = "loginuser"; public $username; public $password; } $request = new LoginRequest(); $request->username = "user"; $request->password = "blah"; 显然这是行不通的

form data into database using jQuery

I have a function in JavaScript with the following parameters below: insertdata(micheal, newyork) I want to be able to insert thus: name = micheal location = newyork into my MySQL database using PHP and jQuery. Both items of data are not coming from a form. I'm only passing them from JavaScript. Since I cannot comment due to reputation, I suggest you a solution that through jQuery y

使用jQuery将数据形成数据库

我有一个JavaScript函数,下面是一些参数: insertdata(micheal, newyork) 我希望能够这样插入: name = micheal location = newyork 到我的MySQL数据库使用PHP和jQuery。 这两项数据都不是来自表单。 我只是通过JavaScript传递它们。 由于我不能评论声誉,我建议你一个解决方案,通过jQuery你可以将它作为隐藏字段附加到当前表单中,并在PHP后端提交,并且可以将其保存在数据库中。 如果您需要关于如何将其附加到表