This question already has an answer here: How to short circuit Array.forEach like calling break? 24 answers The return false is the return of the anonymous function used in the forEach . So it does not return anything for every . If you want to use forEach and return false, you have to do like this : function every(array, predictate) { var result = true; array.forEach(function(x)
这个问题在这里已经有了答案： 如何使Array.forEach短路像调用break？ 24个答案 return false是返回forEach使用的匿名函数。 所以它不会为every返回任何东西。 如果你想使用forEach并返回false，你必须这样做： function every(array, predictate) { var result = true; array.forEach(function(x) { if (!predictate(x)) { result = false; } }); return result; } 你
This question already has an answer here: How to short circuit Array.forEach like calling break? 24 answers You can break out of the loop, but the return value is unused. Since forEach doesn't return anything itself, it wouldn't make much sense to collect return values from the callback. To break out, you need to throw during the callback: var newForEach = function (obj, func, c
这个问题在这里已经有了答案： 如何使Array.forEach短路像调用break？ 24个答案 您可以跳出循环，但返回值未使用。 由于forEach本身不返回任何东西，因此从回调中收集返回值没有什么意义。 要爆发，你需要在回调期间throw ： var newForEach = function (obj, func, con) { if (Pub.isType("Function", func)) { Object.keys(obj).forEach(function (key) { if (func.call(con, obj[key], key,
This question already has an answer here: How to short circuit Array.forEach like calling break? 24 answers 如果在回调中返回真值，可以使用Array#some停止迭代的Array#some 。 var array = [{ name: 'paul', age:20 }, { name: 'john', age:30 }, { name: 'albert', age:40 }], find = function(array, name) { return array.some(function(object) { return object.name === name;
这个问题在这里已经有了答案： 如何使Array.forEach短路像调用break？ 24个答案 如果在回调中返回真值，可以使用Array#some停止迭代的Array#some 。 var array = [{ name: 'paul', age:20 }, { name: 'john', age:30 }, { name: 'albert', age:40 }], find = function(array, name) { return array.some(function(object) { return object.name === name; }); }; console.log(fi
This question already has an answer here: How to short circuit Array.forEach like calling break? 24 answers return value inside foreach 3 answers Javascript数组带有内置函数，称为map，filter等。因此，您可以使用map来遍历数组中的值。 let info = this.array.map((res,key) => { //key can also be accessible return res; }); console.log(info);
这个问题在这里已经有了答案： 如何使Array.forEach短路像调用break？ 24个答案 返回foreach里面的3个答案 Javascript数组带有内置函数，称为map，filter等。因此，您可以使用map来遍历数组中的值。 let info = this.array.map((res,key) => { //key can also be accessible return res; }); console.log(info);
This question already has an answer here: How to short circuit Array.forEach like calling break? 24 answers According to the MDN Javascript docs for forEach : There is no way to stop or break a forEach() loop other than by throwing an exception. Reference: https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/forEach
这个问题在这里已经有了答案： 如何使Array.forEach短路像调用break？ 24个答案 根据forEach的MDN Javascript文档： 没有办法停止或破坏forEach（）循环，而不是抛出异常。 参考：https：//developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/forEach
This question already has an answer here: How to short circuit Array.forEach like calling break? 24 answers There is no way to stop or break a forEach() loop other than by throwing an exception. I think forEach is not suited for your job, use a simple loop instead
这个问题在这里已经有了答案： 如何使Array.forEach短路像调用break？ 24个答案 没有办法停止或破坏forEach（）循环，而不是抛出异常。 我认为forEach不适合您的工作，请改用简单的循环
This question already has an answer here: How to short circuit Array.forEach like calling break? 24 answers forEach is not supposed to break. If you 'd like to break a forEach -like loop, try every or some , which let you break out of the loop. A possible way to re-write your code could be var sum = 0; yourArray.some(function (item) { if (sum > 5) { return true; }
这个问题在这里已经有了答案： 如何使Array.forEach短路像调用break？ 24个答案 forEach不应该打破。 如果你想打破一个forEach的循环，尝试every或some ，让你摆脱循环。 重新编写代码的可能方法可能是 var sum = 0; yourArray.some(function (item) { if (sum > 5) { return true; } sum += item; }); 你无法摆脱forEach 。 只需使用正常的循环 for(var i = 0; i < a; i++){ sum += a
Possible Duplicate: Javascript Array.forEach HowTo break? Given that I have a forEach loop, how do I break out of that loop in case X is true? For example: user.forEach (x,i) -> if x.status == "available" -- I want to break here - Thanks Basically, don't. forEach is meant to be essentially "functional". You could break it
可能重复： Javascript Array.forEach HowTo打破？ 鉴于我有一个forEach循环，如果X是真的，我该如何摆脱这个循环？ 例如： user.forEach (x,i) -> if x.status == "available" -- I want to break here - 谢谢 基本上，不要。 forEach本质上是“功能性”的。 你可以用一个异常来分解它，但是异常应该用于“特殊”条件，而不是控制流。 如果你的意思是打破，你不是
This question already has an answer here: How to short circuit Array.forEach like calling break? 24 answers 不要使用.forEach然后循环： var myObj = [{"a": "1","b": null},{"a": "2","b": 5}] var result = false for(var call of myObj) { console.log(call) var a = call['a'], b = call['b'] if(a == null || b == null) { result = false break } }
这个问题在这里已经有了答案： 如何使Array.forEach短路像调用break？ 24个答案 不要使用.forEach然后循环： var myObj = [{"a": "1","b": null},{"a": "2","b": 5}] var result = false for(var call of myObj) { console.log(call) var a = call['a'], b = call['b'] if(a == null || b == null) { result = false break } }
This question already has an answer here: How to short circuit Array.forEach like calling break? 24 answers From MDN: Note: There is no way to stop or break a forEach() loop other than by throwing an exception. If you need such behaviour, the .forEach() method is the wrong tool, use a plain loop instead. If you are testing the array elements for a predicate and need a boolean return valu
这个问题在这里已经有了答案： 如何使Array.forEach短路像调用break？ 24个答案 来自MDN： 注意：除了抛出异常之外，没有办法停止或中断forEach（）循环。 如果您需要这样的行为，.forEach（）方法是错误的工具，请使用纯循环代替。 如果您正在测试谓词的数组元素并需要布尔返回值，则可以使用every（）或some（）。 return退出当前函数，但迭代继续，所以你得到的下一个项目，跳过if和警报4 ... 如果你需要停止循