This question already has an answer here: For-each over an array in JavaScript? 23 answers Well, for(i in x) works with both, arrays and objects var x = [1, 2, 3]; for(var i in x) console.log(x[i]); var o = {1:1, 2:2, 3:3}; for(var i in o) console.log(o[i]); While for(;;) works only with arrays var x = [1, 2, 3]; for(var i=0; i<x.length; i++) console.log(x[i]); var o = {1:1, 2:2, 3:3
这个问题在这里已经有了答案： 对于JavaScript中的每个数组？ 23个答案 那么， for(i in x)与数组和对象一起工作 var x = [1, 2, 3]; for(var i in x) console.log(x[i]); var o = {1:1, 2:2, 3:3}; for(var i in o) console.log(o[i]); 而for(;;)仅适用于数组 var x = [1, 2, 3]; for(var i=0; i<x.length; i++) console.log(x[i]); var o = {1:1, 2:2, 3:3}; for(var i=0; i<o.length; i++) console.log(x[i]);
This question already has an answer here: For-each over an array in JavaScript? 23 answers The for in is used to iterate over properties on the object. It is not the same as a regular foreach. Use a for loop for this var myArray = ["Bob", "Nancy", "Jessie", "Frank"]; var arrayLength = myStringArray.length; for (var i = 0; i < arrayLength; i++) { //Do something with element myArray
这个问题在这里已经有了答案： 对于JavaScript中的每个数组？ 23个答案 for in用于遍历对象上的属性。 它与普通的foreach不一样。 为此使用for循环 var myArray = ["Bob", "Nancy", "Jessie", "Frank"]; var arrayLength = myStringArray.length; for (var i = 0; i < arrayLength; i++) { //Do something with element myArray[i] } 我想你需要这样的东西。 编辑：你的数组只有4个元素。 在第二行中，我将
This question already has an answer here: For-each over an array in JavaScript? 23 answers A for…in loop in JavaScript loops through an object's keys, not its values. You can use Array.prototype.forEach , given support; $.each works as a fallback too, since you're using jQuery. var textArray = ['#text1', '#text2', '#text3', '#text4', '#text5', '#text6', '#text7',
这个问题在这里已经有了答案： 对于JavaScript中的每个数组？ 23个答案 JavaScript中的for…in循环通过对象的键循环，而不是其值。 你可以使用Array.prototype.forEach ，给予支持; $.each可以作为后备，因为你使用的是jQuery。 var textArray = ['#text1', '#text2', '#text3', '#text4', '#text5', '#text6', '#text7', '#text8']; $('#capture').click(function() { textArray.forEach(function
This question already has an answer here: For-each over an array in JavaScript? 23 answers I'm trying to loop over the MoveParts in javascript like this: for (var movePart in moveResult.MoveParts) { console.log(movePart.From); }; I always get undefined instead of the actual value. Don't use for-in to loop through arrays, that's not what it's for. for-in is for loopin
这个问题在这里已经有了答案： 对于JavaScript中的每个数组？ 23个答案 我试图在JavaScript中循环播放MoveParts，如下所示： for (var movePart in moveResult.MoveParts) { console.log(movePart.From); }; 我总是得到未定义的而不是实际值。 不要使用for-in循环访问数组，这不是它的用途。 for-in用于循环对象属性。 这个答案显示了通过数组循环的各种方法。 你的for-in没有工作的原因是movePart是关键，而不
This question already has an answer here: Access / process (nested) objects, arrays or JSON 18 answers For-each over an array in JavaScript? 23 answers You can do a test like this function representsNumber(str) { return str === (+str).toString(); } // e.g. usage representsNumber('a'); // false representsNumber([]); // false representsNumber(1); // false (it IS a number) representsNum
这个问题在这里已经有了答案： 访问/进程（嵌套）对象，数组或JSON 18个答案 对于JavaScript中的每个数组？ 23个答案 你可以做这样的测试 function representsNumber(str) { return str === (+str).toString(); } // e.g. usage representsNumber('a'); // false representsNumber([]); // false representsNumber(1); // false (it IS a number) representsNumber('1.5'); // true representsNumber('-5.1'); // tr
This question already has an answer here: For-each over an array in JavaScript? 23 answers 使用Array#forEach方法进行数组迭代。 var points = [{ x: 75, y: 25 }, { x: 75 + 0.0046, y: 25 }]; points.forEach(function(obj) { console.log(obj.x, obj.y); }) var points = [{ x: 75, y: 25},{ x: 75+0.0046, y: 25}]; //ES5 points.forEach(function(point){ console.log("x: " + point.
这个问题在这里已经有了答案： 对于JavaScript中的每个数组？ 23个答案 使用Array#forEach方法进行数组迭代。 var points = [{ x: 75, y: 25 }, { x: 75 + 0.0046, y: 25 }]; points.forEach(function(obj) { console.log(obj.x, obj.y); }) var points = [{ x: 75, y: 25},{ x: 75+0.0046, y: 25}]; //ES5 points.forEach(function(point){ console.log("x: " + point.x + " y: " + point.y) })
This question already has an answer here: For-each over an array in JavaScript? 23 answers 使用forEach功能： var array = [{ 'a': '12', 'b': '10' }, { 'a': '20', 'b': '22' }]; array.forEach(function(e) { e.c = +e.b - +e.a }); document.write(JSON.stringify(array)); you can use array.map, and you should use Number() to convert props to numbers for adding: var array = [ {'a': '12', 'b
这个问题在这里已经有了答案： 对于JavaScript中的每个数组？ 23个答案 使用forEach功能： var array = [{ 'a': '12', 'b': '10' }, { 'a': '20', 'b': '22' }]; array.forEach(function(e) { e.c = +e.b - +e.a }); document.write(JSON.stringify(array)); 你可以使用array.map， 你应该使用Number（）将道具转换为数字来添加： var array = [ {'a': '12', 'b':'10'}, {'a': '20', 'b':'22'} ]; var r = arr
This question already has an answer here: For-each over an array in JavaScript? 23 answers 来自jQuery文档： var arr = [ "one", "two", "three", "four", "five" ]; var obj = { one:1, two:2, three:3, four:4, five:5 }; jQuery.each(arr, function() { $("#" + this).text("My id is " + this + "."); return (this != "four"); // will stop running to skip "five" }); jQuery.each(obj, function(i, val)
这个问题在这里已经有了答案： 对于JavaScript中的每个数组？ 23个答案 来自jQuery文档： var arr = [ "one", "two", "three", "four", "five" ]; var obj = { one:1, two:2, three:3, four:4, five:5 }; jQuery.each(arr, function() { $("#" + this).text("My id is " + this + "."); return (this != "four"); // will stop running to skip "five" }); jQuery.each(obj, function(i, val) { $("#" + i).append(do
I am writing a JavaScript section of code and am making huge amounts of silly mistakes in the syntax. But the only way to find what line the error is on is to start commenting out the section of code I just wrote and reload it into the browser to narrow down where my missing ');' is. How do you "compile" a JavaScript source to make sure it is syntactically correct so that I
我正在编写JavaScript代码段，并且在语法上犯了大量愚蠢的错误。 但找到错误的唯一途径是开始评论我刚刚写的代码段并将其重新加载到浏览器中以缩小我缺失的位置的范围）;' 是。 如何“编译”JavaScript源以确保它在语法上是正确的，以便我可以在浏览器中进行调试？ 如果在运行时没有发现错误，请在Firefox中按Ctrl + Shift + J。 当然，萤火虫的效果更好，但这是一种快捷方式。 http://www.javascriptlint.com/ 以
I'm trying to write a simple repeating decimal algorithm. Right now I'm pretty close to having something that works. I tried to use this algorithm: How to know the repeating decimal in a fraction? "A very simple algorithm is this: implement long division. Record every intermediate division you do. As soon as you see a division identical to the one you've done before, you hav
我试图写一个简单的重复小数算法。 现在我非常接近有效的东西。 我试图使用这个算法：如何知道小数中的重复小数？ “一个非常简单的算法就是：实施长期分工，记录你所做的每一个中间分工，只要你看到一个与你之前完成的分工相同的分工，你就有重复的事情。” 除了检测重复的十进制模式并将其放在括号内，我能够完成上述所有操作。 对于7/13的分数，我的输出应该是0. [538461] 现在是0,5,3,8,4,6,1,5,3,8,4,6,1,5,3,8,4,6