Fgets compilation error

I'm stuck with what seems a beginner's compilation error: My simple program: #include <stdlib.h> #include <stdio.h> #include "Tiles_Circular_Linked_List.h" #define MAX_LINE_LENGTH 128; int main(int argc, char **argv) { struct node *head_tail; FILE *file; /*char filename[] = "/home/student/Desktop/Studies/C/testing_fodder/tiles";*/ argv++; /*go to second c

Fgets编译错误

我卡在似乎是一个初学者的编译错误: 我的简单程序: #include <stdlib.h> #include <stdio.h> #include "Tiles_Circular_Linked_List.h" #define MAX_LINE_LENGTH 128; int main(int argc, char **argv) { struct node *head_tail; FILE *file; /*char filename[] = "/home/student/Desktop/Studies/C/testing_fodder/tiles";*/ argv++; /*go to second character-array argument*/ file

Concept behind these four lines of tricky C code

Why does this code give the output C++Sucks ? What is the concept behind it? #include <stdio.h> double m[] = {7709179928849219.0, 771}; int main() { m[1]--?m[0]*=2,main():printf((char*)m); } Test it here. The number 7709179928849219.0 has the following binary representation as a 64-bit double : 01000011 00111011 01100011 01110101 01010011 00101011 00101011 01000011 +^^^^^^^

这些四行棘手的C代码背后的概念

为什么这段代码会输出C++Sucks ? 它背后的概念是什么? #include <stdio.h> double m[] = {7709179928849219.0, 771}; int main() { m[1]--?m[0]*=2,main():printf((char*)m); } 在这里测试。 数字7709179928849219.0具有以下二进制表示形式作为64位double 7709179928849219.0型: 01000011 00111011 01100011 01110101 01010011 00101011 00101011 01000011 +^^^^^^^ ^^^^---- -------- -------- -------

Pass a char pointer array to a function in C?

I have the following code: int main(){ char **array; char a[5]; int n = 5; array = malloc(n *sizeof *array); /*Some code to assign array values*/ test(a, array); return 0; } int test(char s1, char **s2){ if(strcmp(s1, s2[0]) != 0) return 1; return 0; } I'm trying to pass char and char pointer array to a function, but the above code results i

将一个char指针数组传递给C中的函数?

我有以下代码: int main(){ char **array; char a[5]; int n = 5; array = malloc(n *sizeof *array); /*Some code to assign array values*/ test(a, array); return 0; } int test(char s1, char **s2){ if(strcmp(s1, s2[0]) != 0) return 1; return 0; } 我试图将char和char指针数组传递给一个函数,但上面的代码会导致以下错误和警告: temp.c: In function ‘main’:

Understanding an uncommon argument to main

The following question was given in a college programming contest. We were asked to guess the output and/or explain its working. Needless to say, none of us succeeded. main(_){write(read(0,&_,1)&&main());} Some short Googling led me to this exact question, asked in codegolf.stackexchange.com : https://codegolf.stackexchange.com/a/1336/4085 There, its explained what it does : R

理解一个不常见的主要参数

以下问题是在大学编程比赛中提出的。 我们被要求猜测输出和/或解释其工作。 不用说,我们没有人成功。 main(_){write(read(0,&_,1)&&main());} 一些简短的谷歌搜索导致我到这个确切的问题,在codegolf.stackexchange.com问: https://codegolf.stackexchange.com/a/1336/4085 在那里,它解释了它的作用: Reverse stdin and place on stdout ,但不是如何。 我在这个问题中也找到了一些帮助:对主要和其他

C program for GCC and MS Visual Express C++ works only for GCC

I'm trying to make my school assignment to work in both GCC and MS VS enviroments, but for some reason, it fails to compile in MS VS... The errors are: warning C4627: '#include ': skipped when looking for precompiled header use - Add directive to 'Stdafx.h' or rebuild precompiled header or unexpected #endif (the one after #include "Stdafx.h") or When I pu

用于GCC和MS Visual C ++的C程序仅适用于GCC

我试图让我的作业在GCC和MS VS环境中工作,但由于某种原因,它无法在MS VS编译... 错误是: 警告C4627:'#include':在寻找预编译头文件时跳过使用 - 将指令添加到'Stdafx.h'或重建预编译头文件 要么 意外的#endif(#包括“Stdafx.h”之后的那个) 要么 当我把“Stdafx.h”标题放到第一行时,它的行为就像没有stdio一样,一切(HANDLE,INT等)都是非法声明。 #include <stdio.h> #include <s

how to avoid undefined symbols in C

I am trying to make a modular project in C. I am writing a firmware for an embedded ARM CPU. It is composed of different parts, which cannot all be compiled at the same time due to memory limitation. Simplifying, let's say I have a module A which manages all the optional parts of the firmware, each coded in its module (B, C, D, etc...) in module AI use #ifdef clauses: #ifdef USE_B #in

如何避免C中的未定义符号

我正尝试在C中创建一个模块化项目。我正在为嵌入式ARM CPU编写固件。 它由不同的部分组成,由于内存限制,不能同时编译。 简化,假设我有一个模块A,它管理固件的所有可选部分,每个模块都在其模块中编码(B,C,D等等) 在模块AI中使用#ifdef子句: #ifdef USE_B #include "B.h" #endif #ifdef USE_C #include "C.h" #endif ... 然后,除此之外,我只需#define我想包含的模块的关键字。 我在文件Zc中有一些全局

Declare a variable that is Defined in a struct

Consider the following struct defined in ModuleA: typedef struct{ int A; int B; int C[4]; }myStructType; myStructType MyStruct; If I wanted to use this struct from ModuleB, then I would declare the struct in the ModuleA header like this: extern myStructType MyStruct; So far, so good. Other modules can read and write MyStruct by including the Module A header file. Now the quest

声明一个在结构中定义的变量

考虑ModuleA中定义的以下结构: typedef struct{ int A; int B; int C[4]; }myStructType; myStructType MyStruct; 如果我想从ModuleB使用这个结构体,那么我会在ModuleA头文件中声明这样的结构体: extern myStructType MyStruct; 到现在为止还挺好。 其他模块可以通过包含Module A头文件来读写MyStruct。 现在的问题是: 我怎样才能在Module A头文件中声明结构的一部分? 例如,如果我希望ModuleB能够

Is the sizeof(enum) == sizeof(int), always?

Is the sizeof(enum) == sizeof(int), always ? Or is it compiler dependent? Is it wrong to say, as compiler are optimized for word lengths (memory alignment) ie y int is the word-size on a particular compiler? Does it means that there is no processing penalty if I use enums, as they would be word aligned? Is it not better if I put all the return codes in an enum, as i clearly do not worry ab

是sizeof(枚举)== sizeof(int),总是?

是sizeof(枚举)== sizeof(int),总是? 还是它依赖于编译器? 是否错误地说,编译器针对字长(内存对齐)进行了优化,即y int是特定编译器的字大小? 这是否意味着如果我使用枚举没有处理惩罚,因为它们是字对齐的? 如果我把所有的返回码放在一个枚举中,不是更好,因为我显然不担心它的值,只检查返回类型时的名字。 如果是这种情况,#DEFINE会更好,因为它可以节省内存。 通常的做法是什么? 如果我必须通过网

What is the LD

I came across a reference to it recently on proggit and (as of now) it is not explained. I suspect this might be it, but I don't know for sure. If you set LD_PRELOAD to the path of a shared object, that file will be loaded before any other library (including the C runtime, libc.so ). So to run ls with your special malloc() implementation, do this: $ LD_PRELOAD=/path/to/my/malloc.so /bin

什么是LD

我最近在proggit上遇到了一个引用,并且(现在)没有解释它。 我怀疑这可能是它,但我不知道。 如果将LD_PRELOAD设置为共享对象的路径,那么该文件将在任何其他库(包括C运行时, libc.so ) 之前加载。 因此,要使用特殊的malloc()实现运行ls ,请执行以下操作: $ LD_PRELOAD=/path/to/my/malloc.so /bin/ls 您可以通过创建具有相同符号的库并在LD_PRELOAD指定库来覆盖库存库中的符号。 有些人使用它来指定非标准位置

Macros in C (or possibly C++)?

A basic definition and example and a few references for "X-Macros" is given in this wikipedia entry on the C pre-processor: An X-Macro is a header file (commonly using a ".def" extension instead of the traditional ".h") that contains a list of similar macro calls (which can be referred to as "component macros"). What are some good sources of information

C中的宏(或可能是C ++)?

在C预处理器上的维基百科条目中给出了“X-Macros”的基本定义和示例以及一些参考文献: X-Macro是一个头文件(通常使用“.def”扩展名而不是传统的“.h”),它包含一个类似的宏调用列表(可以称为“组件宏”)。 关于如何使用这种强大的技术,有什么好的信息来源? 有没有使用这种方法的知名开源库? 我在代码中使用了X宏()。 该值仅来自仅将新数据添加到“X列表”并且不修改任何其他代码。 X宏()的最常见用法是将错误文本