This question already has an answer here: Cast int to enum in C# 21 answers Convert String to Type in C# [duplicate] 4 answers Enum String Name from Value 6 answers Get the name of Enum value 3 answers Get enum name when value is known 6 answers In addition to the name of enum itself you should know namespace and assembly that enum is declared at. Assuming you run code below in assem
这个问题在这里已经有了答案： 在int C中枚举21枚答案 将字符串转换为在C＃中键入[复制] 4个答案 来自Value 6的Enum字符串名称的答案 获取Enum值3的答案的名称 当值已知6个答案时获取枚举名称 除了enum本身的名称之外，您应该知道enum声明的名称空间和程序集。 假设你在程序集中运行下面的代码，其中定义了枚举，并且所有的枚举都在编译时在同一个命名空间中定义，你可以这样做： string dataType = "Cheese"; int
This question already has an answer here: Cast int to enum in C# 21 answers Just cast the int to the enum . o.MyEnum = (CustomEnumProp) myInt; You can also use the Enum.IsDefined method to check that the int is valid. if (Enum.IsDefined(typeof(CustomEnumProp), myInt)) o.MyEnum = (CustomEnumProp) myInt;
这个问题在这里已经有了答案： 在int C中枚举21枚答案 只需将int转换为enum 。 o.MyEnum = (CustomEnumProp) myInt; 您也可以使用Enum.IsDefined方法来检查int是否有效。 if (Enum.IsDefined(typeof(CustomEnumProp), myInt)) o.MyEnum = (CustomEnumProp) myInt;
Possible Duplicate: Cast int to Enum in C# I fetch a int value from the database and want to cast the value to an enum variable. In 99.9% of the cases, the int will match one of the values in the enum declaration public enum eOrderType { Submitted = 1, Ordered = 2, InReview = 3, Sold = 4, ... } eOrderType orderType = (eOrderType) FetchIntFromDb(); In the edge case, the
可能重复： 在int中将int转换为Enum 我从数据库中获取一个int值，并希望将该值转换为一个枚举变量。 在99.9％的情况下，int将与枚举声明中的一个值匹配 public enum eOrderType { Submitted = 1, Ordered = 2, InReview = 3, Sold = 4, ... } eOrderType orderType = (eOrderType) FetchIntFromDb(); 在边缘情况下，值将不匹配（无论是数据损坏还是手动进入并混淆数据）。 我可以使用switch语句并
This question already has an answer here: Cast int to enum in C# 21 answers Enum ToString with user friendly strings 19 answers 你并不需要任何特别的东西，你可以将你从数据库中得到的整数转换为你的枚举： int valueFromDB = 4; Days enumValue = (Days)valueFromDB; I would not suggest this approach. You need a look-up table for days. For instance create table Days( DaysID INT PRIMARY KEY, Name
这个问题在这里已经有了答案： 在int C中枚举21枚答案 枚举ToString用户友好的字符串19答案 你并不需要任何特别的东西，你可以将你从数据库中得到的整数转换为你的枚举： int valueFromDB = 4; Days enumValue = (Days)valueFromDB; 我不会建议这种方法。 你需要一个查找表几天。 例如 create table Days( DaysID INT PRIMARY KEY, Name VARCHAR(20)) 所有其他表将有一个DaysID的外键列。 我之所以反对你的方法是因
This question already has an answer here: Cast int to enum in C# 21 answers 根据你的枚举声明，Suit在[0..3]范围内，而等级在[1..13]范围内（注意，该等级不是以0为基础的），所以应该纠正内循环： for (int rankVal = 0; rankVal < 13; rankVal++) // <- 14 changed for 13: [0..13] has the same length as [1..14] { cards[suitVal * 13 + rankVal] = new Card((Suits)suitVal, (Rank)(rankVal + 1));
这个问题在这里已经有了答案： 在int C中枚举21枚答案 根据你的枚举声明，Suit在[0..3]范围内，而等级在[1..13]范围内（注意，该等级不是以0为基础的），所以应该纠正内循环： for (int rankVal = 0; rankVal < 13; rankVal++) // <- 14 changed for 13: [0..13] has the same length as [1..14] { cards[suitVal * 13 + rankVal] = new Card((Suits)suitVal, (Rank)(rankVal + 1)); // <- removed -1 from
This question already has an answer here: Cast int to enum in C# 21 answers Just cast the integer to the enum: SpiceLevels level = (SpiceLevels) 3; and of course the other way around also works: int number = (int) SpiceLevels.Ferocious; See also MSDN: Every enumeration type has an underlying type, which can be any integral type except char. The default underlying type of enumeration el
这个问题在这里已经有了答案： 在int C中枚举21枚答案 只需将整数转换为枚举： SpiceLevels level = (SpiceLevels) 3; 当然也可以采用其他方式： int number = (int) SpiceLevels.Ferocious; 另请参阅MSDN： 每个枚举类型都有一个基础类型，可以是除char之外的任何整型。 枚举元素的默认基础类型是int。 ... 但是，显式转换对于从枚举类型转换为整型类型是必需的 enum SpiceLevels { None = 0, Mild = 1, Moderat
Possible Duplicate: Cast int to Enum in C# I got the following enum: public enum detallistaDocumentStatus { /// <remarks/> ORIGINAL, /// <remarks/> COPY, /// <remarks/> REEMPLAZA, /// <remarks/> DELETE, } then I got a class property of type detallistaDocumentStatus: public detallistaDocumentStatus documentStatus { get {
可能重复： 在int中将int转换为Enum 我得到了以下枚举： public enum detallistaDocumentStatus { /// <remarks/> ORIGINAL, /// <remarks/> COPY, /// <remarks/> REEMPLAZA, /// <remarks/> DELETE, } 然后我得到了类型为detallistaDocumentStatus的类属性： public detallistaDocumentStatus documentStatus { get { return this.d
Possible Duplicate: Cast int to enum in C# If I have the following code: enum foo : int { option1 = 1, option2, ... } private foo convertIntToFoo(int value) { // Convert int to respective Foo value or throw exception } What would the conversion code look like? It's fine just to cast your int to Foo: int i = 1; Foo f = (Foo)i; If you try to cast a value that's no
可能重复： 在int中枚举枚举在C＃中枚举 如果我有以下代码： enum foo : int { option1 = 1, option2, ... } private foo convertIntToFoo(int value) { // Convert int to respective Foo value or throw exception } 转换代码是什么样的？ 把你的int投给Foo很好： int i = 1; Foo f = (Foo)i; 如果您尝试转换未定义的值，它仍然有效。 这可能来自唯一的伤害，就是你以后如何使用价值。 如果你确
I'm trying to create a small Excel-Addin with just 1 Project in the Solution. I downloaded the Tools at http://social.msdn.microsoft.com/Forums/vstudio/en-US/0c144a87-917a-4eb1-8716-da61f7efdafc/office-developer-tools-for-visual-studio-2013-march-2014-update-now-available?forum=lightswitch and could create a Add-In. I can even debug it, but as soon as I rebuild the Solution, i get the 2 fo
我正在尝试在解决方案中创建一个只包含1个项目的小型Excel-Addin。 我下载了工具http://social.msdn.microsoft.com/Forums/vstudio/en-US/0c144a87-917a-4eb1-8716-da61f7efdafc/office-developer-tools-for-visual-studio-2013-march -2014-update-now-available？forum = lightswitch并且可以创建一个Add-In。 我甚至可以调试它，但只要我重建解决方案，我得到以下2个错误： 错误1“SignFile”任务不支持“TargetFrameworkVe
Trying to use bearer token based authentification in simple .Net Core Web API project. Here is my Startup.cs app.UseMvc(); //--- const string secretKey = "mysupersecret_secretkey!123"; SymmetricSecurityKey signingKey = new SymmetricSecurityKey(Encoding.UTF8.GetBytes(secretKey)); SigningCredentials signingCredentials = new SigningCredentials(signingKey, SecurityAlgorithms.HmacSha256); //--- cons
尝试在简单的.Net Core Web API项目中使用基于持证者令牌的身份验证。 这是我的Startup.cs app.UseMvc(); //--- const string secretKey = "mysupersecret_secretkey!123"; SymmetricSecurityKey signingKey = new SymmetricSecurityKey(Encoding.UTF8.GetBytes(secretKey)); SigningCredentials signingCredentials = new SigningCredentials(signingKey, SecurityAlgorithms.HmacSha256); //--- const string audience = "Aud