REST Hypermedia URI Changes Based On Context in Web API (HATEOAS)

I am working on a new asp.net web api restful service and spent some time with some Pluralsight courses on the subject. One of the better ones dives deep into design and the implementation of hypermedia (HATEOAS). I followed the implementation in the video as it was very straight forward and being new to mvc/web api it was really helpful to see it working end to end. However as soon as I sta

Web API中基于上下文的REST超媒体URI更改(HATEOAS)

我正在研究一个新的asp.net web api宁静服务,并花了一些时间与一些关于这个主题的Pluralsight课程。 一个更好的人深入设计和实施超媒体(HATEOAS)。 我跟着视频中的实现,因为它非常直接,并且对于mvc / web api是新手,它看起来很有帮助。 然而,只要我开始深入了解我的实现,使用UrlHelper()计算返回链接就开始崩溃。 在下面的代码中,我有一个简单的Get(),它返回一个特定资源的集合,然后返回一个允许返回单个

Is the JsonSerializerSettings thread safe?

If I use the same settings across my project, can I instantiate a single static copy of my JsonSerializerSettings and use that throughout? For example : private static readonly JsonSerializerSettings settings = new JsonSerializerSettings { Formatting = Formatting.Indented, TypeNameHandling = TypeNameHandling.None, DateFormatHandling = DateFormatHandling.Iso

JsonSerializerSettings线程安全吗?

如果我在我的项目中使用相同的设置,是否可以实例化我的JsonSerializerSettings的一个静态副本并将其用于整个过程? 例如 : private static readonly JsonSerializerSettings settings = new JsonSerializerSettings { Formatting = Formatting.Indented, TypeNameHandling = TypeNameHandling.None, DateFormatHandling = DateFormatHandling.IsoDateFormat, TypeNameAssemblyForm

Why should we typedef a struct so often in C?

I have seen many programs consisting of structures like the one below typedef struct { int i; char k; } elem; elem user; Why is it needed so often? Any specific reason or applicable area? As Greg Hewgill said, the typedef means you no longer have to write struct all over the place. That not only saves keystrokes, it also can make the code cleaner since it provides a smidgen more a

为什么我们应该在C中经常输入一个结构体?

我看过很多程序,包括下面的结构 typedef struct { int i; char k; } elem; elem user; 为什么需要这么频繁? 任何特定原因或适用区域? 正如Greg Hewgill所说,typedef意味着您不必再遍布整个地方写struct 。 这不仅可以节省击键次数,还可以使代码更清洁,因为它提供了更多的抽象。 东西喜欢 typedef struct { int x, y; } Point; Point point_new(int x, int y) { Point a; a.x = x; a.y = y; r

Scanning and printing variable data type "double" in C

I'm studying algorithms and would love to learn. My problem is this, I can't output a number "600851475143" using the integer data type in C. So I switched to doubles. However the output is "0.0000". Can someone kindly tell me what I'm doing wrong? I simply want to scan and print any number in the double data type then I'm going to focus on getting the high

在C中扫描和打印可变数据类型“double”

我正在学习算法,很想学习。 我的问题是,我不能使用C中的整数数据类型输出数字“600851475143”。所以我切换到双打。 但是输出是“0.0000”。 有人可以告诉我我做错了什么吗? 我只是想扫描并打印双数据类型中的任何数字,然后我将重点放在获取最高的主要因素:) #include <stdio.h> #include <math.h> int main() { double number; double div = 2; double highest = 2; printf("Please input a number: "); scan

Why does the addition of two float numbers is incorrect in C?

I have a problem with the addition of two float numbers. Code below: float a = 30000.0f; float b = 4499722832.0f; printf("%fn", a+b); Why the output result is 450002816.000000? (The correct one should be 450002832.) Float are not represented exactly in C - see http://en.wikipedia.org/wiki/Floating_point#IEEE_754:_floating_point_in_modern_computers and http://en.wikipedia.org/wiki/Single_pr

为什么在C中添加两个浮点数不正确?

我遇到了两个浮点数的问题。 代码如下: float a = 30000.0f; float b = 4499722832.0f; printf("%fn", a+b); 为什么输出结果是450002816.000000? (正确的应该是450002832.) 浮点数在C中没有完全表示 - 请参见http://en.wikipedia.org/wiki/Floating_point#IEEE_754:_floating_point_in_modern_computers和http://en.wikipedia.org/wiki/Single_precision,因此使用float计算只能给出近似值结果。 这对于较大的值尤

Comparison of float and double variables

Possible Duplicates: Difference between float and double strange output in comparision of float with float literal I am using visual C++ 6.0 and in a program I am comparing float and double variables For example for this program #include<stdio.h> int main() { float a = 0.7f; double b = 0.7; printf("%d %d %d",a<b,a>b,a==b); return 0; } I am getting 1 0

浮点和双变量的比较

可能重复: 浮动和双重之间的区别 在浮点数和浮点数之间进行比较的奇怪输出 我正在使用Visual C ++ 6.0,并在一个程序中比较float和double变量例如这个程序 #include<stdio.h> int main() { float a = 0.7f; double b = 0.7; printf("%d %d %d",a<b,a>b,a==b); return 0; } 我得到1 0 0作为输出 和 #include<stdio.h> int main() { float a = 1.7f; double

Lag when changing color of button border on WP8

I'm moving a object over a bunch of Buttons, and when this object is over a button I change the color of the border. This is no problem, I can do this through bindings, storyboards or style setters/Visual state. When I run this on my emulator it works nice and smooth, but when I run it on my windows phone, there is a small lag when the Border of the country changes. Is there a way to avoid

更改WP8上按钮边框的颜色时出现延迟

我将一个对象移动到一堆按钮上,当此对象位于按钮上方时,我将更改边框的颜色。 这不是问题,我可以通过绑定,故事板或样式设置器/视觉状态来完成此操作。 当我在我的模拟器上运行它时,它运行的很好,很顺利,但是当我在Windows Phone上运行它时,国家边界发生变化时会有一点滞后。 有没有办法避免这种情况? 1.代码示例 <Button x:Name="Button1" BorderThickness="0" BorderBrush="Transparent"> <Button.T

How to allocate aligned memory only using the standard library?

I just finished a test as part of a job interview, and one question stumped me - even using google for reference. I'd like to see what the stackoverflow crew can do with it: The “memset_16aligned” function requires a 16byte aligned pointer passed to it, or it will crash. a) How would you allocate 1024 bytes of memory, and align it to a 16 byte boundary? b) Free the memory after the mem

如何仅使用标准库分配对齐的内存?

作为面试的一部分,我刚刚完成了一项测试,其中一个问题难倒我 - 甚至使用谷歌作为参考。 我想看看stackoverflow的工作人员可以用它做些什么: “memset_16aligned”函数需要传递一个16byte对齐的指针,否则它会崩溃。 a)如何分配1024字节的内存,并将其与16字节的边界对齐? b)在memset_16aligned执行后释放内存。 { void *mem; void *ptr; // answer a) here memset_16aligned(ptr, 0, 1024); // a

Can I rely on malloc returning NULL?

I read that on Unix systems, malloc can return a non-NULL pointer even if the memory is not actually available, and trying to use the memory later on will trigger an error. Since I cannot catch such an error by checking for NULL, I wonder how useful it is to check for NULL at all? On a related note, Herb Sutter says that handling C++ memory errors is futile, because the system will go into spa

我可以依靠malloc返回NULL吗?

我在Unix系统上读到,即使内存实际上不可用, malloc也可以返回一个非NULL指针,并且稍后尝试使用内存会触发错误。 由于我无法通过检查NULL来捕捉这样的错误,我不知道检查NULL是多么有用吗? 在相关说明中,Herb Sutter说,处理C ++内存错误是徒劳的,因为在实际发生异常之前系统会长期处于分页痉挛状态。 这也适用于malloc吗? 引用Linux手册: 默认情况下,Linux遵循乐观的内存分配策略。 这意味着当malloc()返回非N

8 to base64 string

I'm trying to convert UTF-8 to base64 string. Example: I have "abcdef==" in UTF-8 . It's in fact a "representation" of a base64 string. How can I retrieve a "abcdef==" base64 string (note that I don't want a "abcdef==" "translation" from UTF-8 , I want to get a string encoded in base64 which is "abcdef=="). EDIT As m

8到base64字符串

我试图将UTF-8转换为base64字符串。 例如:我在UTF-8有“abcdef ==”。 它实际上是base64字符串的“表示”。 我怎么能检索一个“abcdef ==” base64字符串(注意,我不想从UTF-8 “abcdef ==”“翻译”,我想获得一个在base64中编码的字符串,它是 “abcdef ==” )。 编辑 由于我的问题似乎不清楚,这里有一个重新说明: 我的字节数组(假设我将其命名为A)由base64字符串表示。 将A转换为base64会给我“abcdef ==”。 此字符串