Does Tomcat use a different Java Virtual Machine (JVM) for each web application running in its container, or does all web applications in Tomcat run under the same JVM? So for a specific example: if a web application under webapps, enables JMX programmatically (via System properties) does this mean that JMX is enabled for all web applications running in the container? I believe this is the ca
Tomcat是否对其容器中运行的每个Web应用程序使用不同的Java虚拟机（JVM），或者Tomcat中的所有Web应用程序是否都在相同的JVM下运行？ 因此，对于特定的示例：如果Web应用程序下的Web应用程序以编程方式启用JMX（通过系统属性），这是否意味着对容器中运行的所有Web应用程序都启用了JMX？ 我相信是这样，但是想确认一下。 这个问题来自我在这个线程中的问题：关于tomcat和jmx的问题。 任何关于这个问题的意见都会被赞赏
We have a Java web application and we'd like to set up some basic monitoring with a view to expanding this monitoring in future. Our plan is as follows: (1) Collect generic information (eg memory and threads) about the virtual machine of the web container that application is running in. (2) Monitor the "state" of the application. This is rather vague but at the least we'd
我们有一个Java Web应用程序，我们希望设置一些基本的监控，以期在未来扩展这种监控。 我们的计划如下： （1）收集关于运行应用程序的Web容器的虚拟机的通用信息（例如内存和线程）。 （2）监视应用程序的“状态”。 这是相当模糊的，但至少我们想看看Web应用程序是否仍然存在，并且可以响应请求。 （3）将来我们希望收集更多针对我们应用的信息。 这又相当模糊，但您可以假设我们可能希望通过支持人员可用的应用程序在内
Here is a situation where in a message refuses to deliver itself to the consumer due to improper handling by the client and therefore this message bounces infinitely between the server and the client resulting into continuous stream of log messages which fills up the disk space. How to avoid this situation? Or in other words how to restrict the retry to a limited number of times? I tried ret
在这种情况下，由于客户端的不正确处理，消息拒绝将消息传递给消费者，因此此消息在服务器和客户端之间无限次地反弹，导致连续的日志消息流填满磁盘空间。 如何避免这种情况？ 或换句话说，如何限制重试次数有限？ 我试着用兔子模板重试模板，但没有成功。 请找到下面的配置： <rabbit:template id="rabbitTemplate" connection-factory="connectionFactory" reply-timeout="10" retry-template="retryTemplate"/>
I am adding messages to rabbitmq queue using spring amqp template in my spring batch item writer. public class AmqpAsynchRpcItemWriter<T> implements ItemWriter<T> { protected String exchange; protected String routingKey; protected String queue; protected String replyQueue; protected RabbitTemplate template; BlockingQueue<Object> blockingQueue; pub
我在spring批处理项目编写器中使用spring amqp模板将消息添加到rabbitmq队列中。 public class AmqpAsynchRpcItemWriter<T> implements ItemWriter<T> { protected String exchange; protected String routingKey; protected String queue; protected String replyQueue; protected RabbitTemplate template; BlockingQueue<Object> blockingQueue; public void onMessage(Obj
Given a basic MessageListener implementation which consumes messages from a RabbitMQ queue, how can I send the message to different dead-letter-queues based on the type of exceptions that could be thrown while processing it? The queue were the messages are originally published has the x-dead-letter-exchange and x-dead-letter-routing-key set on it, but this is not enough in my case. In case it
给定一个基本的MessageListener实现，它使用来自RabbitMQ队列的消息，如何根据处理它时可能引发的异常类型将消息发送到不同的死信队列？ 队列中最初发布的消息具有x-dead-letter-exchange和x-dead-letter-routing-key设置，但在我的情况下这还不够。 如果它很重要，我的应用程序正在使用Spring 4和Spring Amqp。 据我了解RabbitMQ文档和Spring AMQP，不可能根据代码内部的条件向不同的DLQ发送消息。 我这样说的原因是，我
I wrote Java application, that sends messages to RabbitMQ. Then Flume picks messages up from RabbitMQ queue. I'm interested that nobody pulls messages from the queue, except flume. My application uses Spring AMQP Java plugin. The problem: With the code below, message comes to RabbitMQ queue and stays 'Unknowledges' for ever. As I understand, RabbitMQ is waiting for ACK from M
我编写了Java应用程序，它将消息发送到RabbitMQ。 然后Flume从RabbitMQ队列中选择消息。 我感兴趣的是没有人从队列中拉出消息，除了水槽。 我的应用程序使用Spring AMQP Java插件。 问题： 使用下面的代码，消息进入RabbitMQ队列并永远保持“未知状态”。 据我所知，RabbitMQ正在等待来自MessageListener的ACK，但MessageListener绝不会确认。 有谁知道如何解决它？ 代码： public class MyAmqpConfiguration { @
I want to run a single unit test and collect its "profiling" information: how often every method was called, how many instances of certain class were created, how much time did it take to execute certain method/thread, etc. Then, I want to compare this information with some expected values. Are there any Profilers for Java than let me do this (all this should be done automatically, wit
我想运行一个单元测试并收集其“分析”信息：每个方法被调用的频率，某个类创建了多少个实例，执行特定方法/线程需要多长时间等等。然后，我想要将此信息与一些预期值进行比较。 有没有Java的Profiler比让我这样做（所有这些都应该自动完成，当然，没有任何GUI或用户交互）？ 这是我希望它工作的方式： public class MyTest { @Test public void justTwoCallsToFoo() { Profiler.start(Foo.class); Foo foo = new F
I have studied some of the related posts about this topic and I have learned that when we make a variable of the same name in a subclass, that's called hiding. class A { int i = 10; public void printValue() { System.out.print("Value-A"); System.out.println(i); } } class B extends A { int i = 12; public void printValue() { System.out.print("Value
我研究了一些关于这个主题的相关文章，并且我已经了解到，当我们在子类中创建一个相同名称的变量时，这就是所谓的隐藏。 class A { int i = 10; public void printValue() { System.out.print("Value-A"); System.out.println(i); } } class B extends A { int i = 12; public void printValue() { System.out.print("Value-B"); System.out.println(i); } } publi
I'm trying to load a String from topicRNG to changeXML. I've loaded variables between classes before but can't get it to work now. Firstly I have my code where I try to load it. package XMLTest; public class ModifyTTXML { public static void main(String args[]){ TopicRNG.main(); String something = TopicRNG.topicFinal; ... And then the code where I tr
我试图从topicRNG加载一个String到changeXML。 我之前在类之间加载了变量，但现在无法使用它。 首先，我有我的代码，我尝试加载它。 包XMLTest; public class ModifyTTXML { public static void main(String args[]){ TopicRNG.main(); String something = TopicRNG.topicFinal; ... 然后，我尝试加载它的代码， import java.util.Random; public final class TopicRNG { public stat
我在我的电脑上安装了Java，但是当我运行任何Java程序时，它说错误。我尝试了下面的代码 public class Main { public static void main(String[] args) { System.out.print("This is just an example..."); } } The code you have does not have any problem at all. public class Main { public static void main(String[] args) { System.out.print("This is
我在我的电脑上安装了Java，但是当我运行任何Java程序时，它说错误。我尝试了下面的代码 public class Main { public static void main(String[] args) { System.out.print("This is just an example..."); } } 你所拥有的代码根本没有任何问题。 public class Main { public static void main(String[] args) { System.out.print("This is just an example...