PHP objects in array copy

I got a strange behaviour in PHP with arrays and objects, that I don't understand. Maybe you guys can help me with that. Creating an array, copy it to another array, change a value in the 2nd array and everything is as expected: $array1['john']['name'] = 'foo'; $array2 = $array1; $array2['john']['name'] = 'bar'; echo $array1['john']['name']; // foo echo $array2['john']['name']; // bar N

数组副本中的PHP对象

我在PHP中使用数组和对象得到了一个奇怪的行为,我不明白。 也许你们可以帮助我。 创建一个数组,将其复制到另一个数组,更改第二个数组中的值,并且所有内容都如预期的那样: $array1['john']['name'] = 'foo'; $array2 = $array1; $array2['john']['name'] = 'bar'; echo $array1['john']['name']; // foo echo $array2['john']['name']; // bar 现在,如果我使用该数组中的对象执行此操作,则复制数组中的对象会拥有某

More About PHP OOP

I have been told that a class cannot be defined within a class in PHP. However, in my own example this seems to work which has me confused: class_test.php: require('class_1.php'); new class_1 //Need $missing_variable here. class_1.php class class_1{ public function function_1(){ function callback_function(){ echo "A Callback"; $missing_variable = "Where D

更多关于PHP OOP

我被告知一个类不能在PHP中的类中定义。 然而,在我自己的例子中,这似乎工作,让我感到困惑: class_test.php: require('class_1.php'); new class_1 //Need $missing_variable here. class_1.php class class_1{ public function function_1(){ function callback_function(){ echo "A Callback"; $missing_variable = "Where Did I Go?"; } require('class_2.php'

How can I use a callback function which is stored as a class member in PHP?

Consider the following code, which is a scheme of storing a callback function as a member, and then using it: class MyClass { function __construct($callback) { $this->callback = $callback; } function makeCall() { return $this->callback(); } } function myFunc() { return 'myFunc was here'; } $o = new MyClass(myFunc); echo $o->makeCall(); I would expect myFunc was her

我如何使用在PHP中作为类成员存储的回调函数?

考虑下面的代码,这是一个将回调函数存储为成员的方案,然后使用它: class MyClass { function __construct($callback) { $this->callback = $callback; } function makeCall() { return $this->callback(); } } function myFunc() { return 'myFunc was here'; } $o = new MyClass(myFunc); echo $o->makeCall(); 我希望myFunc was here得到回应,但我得到: Call to undefined method MyClas

PHP Variables, classes and inheritance understanding the basics

I am working on a PHP project and I need some help with the basics. I have a Vehicle class. Within the vehicle class there is a variable called fuel_capacity. As you would expect the fuel capacity changes from vehicle to vehicle. So for example the fuel_capacity changes between a car and a truck. I have a Car class and a Truck class that extend the vehicle class. On construction of the car

PHP变量,类和继承了解基础知识

我正在开发一个PHP项目,我需要一些基础知识。 我有一个车辆类。 在车辆级别中有一个名为fuel_capacity的变量。 正如您所期望的那样,车辆之间的燃油容量会发生变化。 例如,汽车和卡车之间的fuel_capacity会发生变化。 我有一个汽车类和一个卡车类,延长车辆类。 在建造汽车时,我想给$ fuel_capacity分配一个值。 当我这样做时,除非我公布$ fuel_capacity,否则我无法从车辆内的功能访问$ fuel_capacity。 问题是如

PHP DateTime::createFromFormat not working

DateTime::createFromFormat doesn't appear to be working correctly, does anyone know a reason and/or how to fix it? Given this code: var_dump(DateTime::createFromFormat('m', '02')->format('m')); var_dump(DateTime::createFromFormat('n', '2')->format('n')); My expected output would be 02 2 However I actually get: 03 3 Example: http://codepad.viper-7.com/e4hns6 I've tested thi

PHP日期时间:: createFromFormat不工作

DateTime::createFromFormat似乎没有正常工作,有谁知道一个原因和/或如何解决它? 鉴于此代码: var_dump(DateTime::createFromFormat('m', '02')->format('m')); var_dump(DateTime::createFromFormat('n', '2')->format('n')); 我的预期产出是 02 2 但是我实际上得到: 03 3 例如:http://codepad.viper-7.com/e4hns6 我已经在多台服务器上测试过这些服务器,其中包括: 赢得PHP 5.4 Linux PHP 5.3 Vi

Problems with ValidatorConstraint in Symfony 2.5

after upgrading from Symfony 2.4 to 2.5 my form validator constraints are not working any more. I get: Catchable fatal error: Argument 1 passed to SymfonyComponentFormExtensionValidatorTypeFormTypeValidatorExtension::__construct() must be an instance of SymfonyComponentValidatorValidatorInterface, instance of SymfonyComponentValidatorValidatorRecursiveValidator given, defined in vendor/symfony/

Symfony 2.5中ValidatorConstraint的问题

从Symfony 2.4升级到2.5后,我的表单验证器约束无法工作。 我得到:可捕获的致命错误:传递给Symfony Component Form Extension Validator Type FormTypeValidatorExtension :: __ construct()的参数1必须是Symfony Component Validator ValidatorInterface的一个实例,Symfony Component Validator 给定的Validator RecursiveValidator,在第36行中的vendor / symfony / symfony / src / Symfony / Component /

Validate checkbox not mapped to entity in a symfony2 form

I add a non mapped field to a symfony2 form type: $builder->add('terms','checkbox', array('mapped' => false, 'constraints' => array(new NotBlank()))); But the NotBlank() constraint is not working! Only if I change the type from 'checkbox' to 'text' it is working as expected. So how can I validate a checkbox? Of course I tried with 'True()', 'Equal

验证复选框未以symfony2格式映射到实体

我将一个非映射字段添加到symfony2表单类型中: $builder->add('terms','checkbox', array('mapped' => false, 'constraints' => array(new NotBlank()))); 但NotBlank()约束不起作用! 只有当我从“复选框”更改为“文本”时,它才能按预期工作。 那么我如何验证复选框? 当然,我也尝试过使用'True()','EqualTo()'和'Length(...)'约束。 但没有成功。 我也尝试了不同的P

Symfony2 validation component from XML

I am trying to use the Symfony2 validation component in a pre-existing framework which has an existing form handling system done using XSLT. sample from : http://symfony.com/doc/master/book/validation.html <constraint-mapping xmlns="http://symfony.com/schema/dic/constraint-mapping" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://symfony.com/schema/dic/

来自XML的Symfony2验证组件

我试图在已有的使用XSLT完成表单处理系统的框架中使用Symfony2验证组件。 sample from : http://symfony.com/doc/master/book/validation.html <constraint-mapping xmlns="http://symfony.com/schema/dic/constraint-mapping" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://symfony.com/schema/dic/constraint-mapping http://symfony.com/schema/dic/constraint-mapping/cons

Symfony2 Validating an optional field

In my form, I have a field with required option set to false, this field is optional. However, I would like to have a notBlank validation on this field when the field is used: @AssertNotBlank( * message="The name field can't be blank", * groups={"flow_poemDataCollector_step1"} * ) Right now, I can't use the validation constraint NotBlank because it will cause my form validation

Symfony2验证可选字段

在我的表单中,我有一个必填选项设置为false的字段,此字段是可选的。 但是,我希望在使用该字段时对此字段进行notBlank验证: @AssertNotBlank( * message="The name field can't be blank", * groups={"flow_poemDataCollector_step1"} * ) 现在,我无法使用验证约束NotBlank,因为它会导致我的表单验证在该字段未使用时失败。 我试着在onPostBindRequest监听器的字段中添加一个随机值,但它很复杂,并没有设

how to add validation to unbound form field in symfony2

I am trying to validate an unbound field in my symfony2 form. I have googled it and found several similar solutions, so I did a copy-paste and put my own stuff in there, but it doesn't work for me. There is probably a use statement or something that was missing from all the solutions I read, omitted because everyone would know them to be necessary.. .except the rookie here that is. My co

如何为symfony2中的未绑定表单字段添加验证

我试图在我的symfony2表单中验证一个未绑定的字段。 我搜索了它,发现了几个类似的解决方案,所以我做了一个复制粘贴并将自己的东西放在那里,但它对我不起作用。 可能有一个使用声明或者是我读过的所有解决方案中都没有的东西,因为每个人都知道它们是必要的,所以省略了。除了这里的菜鸟。 我的代码: <?php namespace BizTVUserBundleForm; use SymfonyComponentFormAbstractType; use SymfonyComponentFormFormBui