Greetings, Been going around in circles trying to figure out why this will not work. Making a low security log-in system using cookies due to an issue with sessions on the device being used. The set cookie works on its own but either is not setting properly in this script or is not being read properly on the auth script. Also, after the cookie should be set, it is not in the browser. Ideas?
问候， 一直在试图弄清楚为什么这不起作用。 由于所用设备上的会话存在问题，因此使用Cookie制作低安全性登录系统。 设置的cookie可以独立运行，但是在脚本中没有正确设置，或者在auth脚本中没有正确读取。 另外，在设置cookie之后，它不在浏览器中。 想法？ 登录 <?php //If passwords match, a cookie is created if ($pw = $hashedpw) { $memberID = "1221"; //Pulled from DB setco
I am new to PHP. I am trying to get the Header from the response after sending the php curl POST request. The client sends the request to the server and server sends back the response with Header. Here is how I sent my POST request. $client = curl_init($url); curl_setopt($client, CURLOPT_CUSTOMREQUEST, "POST"); curl_setopt($client, CURLOPT_POSTFIELDS, $data_string); curl_setopt(
我是PHP新手。 我试图在发送php curl POST请求后从响应中获取Header。 客户端发送请求到服务器，服务器用Header发回响应。 以下是我发送POST请求的方式。 $client = curl_init($url); curl_setopt($client, CURLOPT_CUSTOMREQUEST, "POST"); curl_setopt($client, CURLOPT_POSTFIELDS, $data_string); curl_setopt($client, CURLOPT_HEADER, 1); $response = curl_exec($client); var_dump($response);
I need to send "500 Internal Server Error" from an PHP script under certain conditions. The script is supposed to be called by a third party app. The script contains a couple of die("this happend") statements for which I need to send the 500 Internal Server Error response code instead of the usual 200 OK . The third party script will re-send the request under certain condit
我需要在某些条件下从PHP脚本发送“500内部服务器错误”。 脚本应该由第三方应用程序调用。 该脚本包含一些我需要发送500 Internal Server Error响应代码而不是通常的200 OK的die("this happend")语句。 第三方脚本将在某些情况下重新发送请求，包括未收到200 OK响应代码。 问题的第二部分：我需要像这样设置我的脚本： <?php custom_header( "500 Internal Server Error" ); if ( that_happened ) {
I'm experiencing an issue in CakePHP 2.0 whereby my flash does not render as expected. Consider the following example of my configuration: appViewLayoutsdefault.ctp: <!-- flash echoed below --> <div id="main_flash"> <?PHP echo $this->Session->flash(); ?> </div> appViewObjectsindex.ctp: <!-- no flash echoed here --> appViewObjectedit.ctp: <!-- flash ech
我在CakePHP 2.0中遇到了一个问题，我的Flash不能按预期呈现。 考虑下面的配置示例： 应用程序查看布局 default.thtml中： <!-- flash echoed below --> <div id="main_flash"> <?PHP echo $this->Session->flash(); ?> </div> 应用程序查看对象 index.ctp： <!-- no flash echoed here --> 应用程序查看对象 edit.ctp： <!-- flash echoed below --> <div id="edit_flash"> &
Unless I have misunderstood how round() function works in PHP, I think there is a bug in it: Example: Running: $prod = 201.6 * 0.000275; echo "No Round..: " . $prod; echo "With Round: " . round($prod, 2, PHP_ROUND_HALF_DOWN); PHP Returns: No Round..: 0.05544 With Round: 0.06 What I expect: With Round, I expected 0.05 as a result. Is this expected result right? Enviroment: P
除非我误解了round（）函数在PHP中的工作方式，否则我认为它存在一个错误： 例： 运行： $prod = 201.6 * 0.000275; echo "No Round..: " . $prod; echo "With Round: " . round($prod, 2, PHP_ROUND_HALF_DOWN); PHP返回： No Round..: 0.05544 With Round: 0.06 我期望的是： 结合Round，我预计结果为0.05。 这是预期的结果吗？ 环境： 使用Apache 2.2.17在Windows 7 64位上运行的PHP 5.3.4。 很多。
I am trying to get at the cURL error number, but the curl_errorno() function doesn't seem to work. If I make a one-line script: curl_errorno(); I get this error: Call to undefined function curl_errorno()... cURL is installed... I can use it to make requests just fine. PHP 5.3.6 (as reported by php.ini) cURL 7.19.7 (as reported by php.ini) My configure command contained --with-cur
我试图得到cURL错误号，但curl_errorno()函数似乎不起作用。 如果我制作一行脚本： curl_errorno(); 我得到这个错误： 调用未定义的函数curl_errorno（）... cURL已安装...我可以使用它来提出请求。 PHP 5.3.6（由php.ini报告） cURL 7.19.7（由php.ini报告） 我的配置命令包含--with-curl 任何想法为什么curl_errorno()不可用？ curl_errno(); 不curl_errorno(); http://www.jonasjohn.de/snippets/php/curl
I'm using WAMP on windows, which installs PHP, Apache and MySQL. I'm now working on something new that requires PostgreSQL. The current install won't do it for me, as I keep getting these errors: Call to undefined function pg_query() Always undefined function I've installed PostgreSQL 8.3.7-1 for windows, added php_pgsql.dll , php_pdo_pgsql.dll and even libpq.dll , whic
我在Windows上使用WAMP，它安装PHP，Apache和MySQL。 我现在正在研究一些需要PostgreSQL的新东西。 目前的安装不会为我做，因为我不断收到这些错误： 调用未定义的函数pg_query（） 总是 未定义的功能 我为Windows安装了PostgreSQL 8.3.7-1，添加了php_pgsql.dll ， php_pdo_pgsql.dll ，甚至是libpq.dll ，在postgreSQL的PHP页面上有一个注释说Windows用户需要从PHP 5.2.6开始 不过，我不断收到这些错误... 有
I'm pretty new to php and I am trying to figure out how to use sessions to check and see if a user is logged into a website so that they would have authorization to access specific pages. Is this something that is complicated or is it because I am a noob that I can't figure it out? Thanks for the help! Logins are not too complicated, but there are some specific pieces that almost al
我很新的PHP，我想弄清楚如何使用会话来检查并查看用户是否登录到网站，以便他们有权访问特定页面。 这是一件复杂的事情，还是因为我是一个白痴，我无法弄清楚？ 谢谢您的帮助！ 登录不是太复杂，但是几乎所有登录过程都需要一些特定的部分。 首先，请确保在需要了解登录状态的所有页面上启用会话变量，方法是将这些变量放在这些页面的开头： session_start(); 接下来，当用户通过登录表单提交用户名和密码时，您通常
我有一个第三方脚本，想知道如何在PHP之前检查session_start()是否在做某事之前已经声明？ something like if(isset($_session_start())) { //do something } if(!isset($_SESSION)) { session_start(); } 该检查将允许您保持当前会话处于活动状态，即使它是一个循环提交应用程序，如果您计划在数据输入不正确时重新使用表单，或者在继续执行下一个程序之前在程序中进行了其他检查和平衡，那么该循环提交应用程序仍然有效。
我有一个第三方脚本，想知道如何在PHP之前检查session_start()是否在做某事之前已经声明？ something like if(isset($_session_start())) { //do something } if(!isset($_SESSION)) { session_start(); } 该检查将允许您保持当前会话处于活动状态，即使它是一个循环提交应用程序，如果您计划在数据输入不正确时重新使用表单，或者在继续执行下一个程序之前在程序中进行了其他检查和平衡，那么该循环提交应用程序仍然有效。
I'm just wondering why this code returns 1 $complete = 'complete'; $completed = ($complete == 'complete') ?: 'Not Complete'; while if I try this one $complete = 'complete'; $completed = ($complete == 'complete') ? $complete : 'Not Complete'; and this one $complete = 'complete'; if ($complete == 'complete') { $completed = $complete; } else { $completed = 'Not Complete'; } they bo
我只是想知道为什么这个代码返回1 $complete = 'complete'; $completed = ($complete == 'complete') ?: 'Not Complete'; 而如果我尝试这一个 $complete = 'complete'; $completed = ($complete == 'complete') ? $complete : 'Not Complete'; 和这个 $complete = 'complete'; if ($complete == 'complete') { $completed = $complete; } else { $completed = 'Not Complete'; } 他们都返回'complete'